Calculate the period of a pendulum that has a length = 0.7 m
Calculate the length in meters of a simple pendulum that has a period of 3.00s if it is located at sea level where gravity is 9.81 m/s2 L = _______________
4) a) Calculate the period of a simple pendulum if the length of the string is g on the moon. gon Moon is 16of g on Earth. gon Earth = 9.8 m/s: 1.5 meter? b) Calculate the period of the simple pendulum if you take to Mars. g on Mars 3.7 m/s What is the ratio of the period of the above simple pendulum to the period of a simple pendulum which is 4 times longer? b) d) What happens...
A simple pendulum consisting of a small object of mass m attached to a string of length 1 has a period T. A pendulum with which of the following combinations of object mass and string length will also have period T?
13.11 A pendulum has a length of 4.8 m. a) At a location where the acceleration due to gravity is 9.80 m/s, what is the period of the pendulum? b) If the period of a pendulum is twice as much the value found in part a, what is the length?
To calculate the period of a pendulum from the equation used in this experiment, which of the following provides sufficient information? Question 3 options: a) the acceleration due to gravity (g) b) the length (L) of the pendulum c) the mass (m) and length (L) of the pendulum t d) he mass (m) and acceleration due to gravity (g) e)the acceleration due to gravity (g) and length (L) of the pendulum
Suppose we have a pendulum of length L = 2.5 m, what is the period of a pendulum when it executes simple harmonic motion?
on a newly discovered planet, the period of a pendulum with a length of 2 m is found to be 5 seconds. what is the acceleration due to gravity on this new planet?
What is the length of a pendulum (on Earth) that has a period of 0.639 s? .
1. If placed at the surface of Earth, a physical pendulum has a period of 1.8 seconds. What will be the period of the same pendulum at the surface of the Moon (gMoon = 1.62 m/s2)? The period at the Moon's surface, T = Units in s 2. The same pendulum is placed at the surface of an unknown planet X. What is the free fall acceleration at the surface of this planet if the pendulum has a period of 1.17...
A simple pendulum has a period of 1.74 s. What is its length? The acceleration due to gravity is 9.8 m/s2 . Answer in units of m.