Question

22.012, Consider the following figure. Note: The currents are not necessarily in the direction shown. (Assume R1 R2 = 5.5 12, and V = 39 V.) R1 2412 124 + R2 1, (a) Find the current in each resistor of the figure above by using the rules for resistors in series and parallel. 5.5.12 Your response differs from the correct answer by more than 100%. A 22.022 A 24 Ω A (b) Write three independent equations for the three currents using Kirchoff's laws: one with the node rule; a second using the loop rule through the battery, the 5.5-12 resistor, and the 24.0-12 resistor; and the third using the loop rule through the 22.0-12 and 24.0-12 resistors. Solve to check the answers found in part (a). (Submit a file with a maximum size of 1 MB.) Choose File No file chosen

Answer 1

AR 25 HRIF B 12 Iz E R12222 R2 = 5.52 V= 39V D 292 Izage R equivalent resistance . a and Rag 6 gol 39) Amp 5 7 t av between Ri and 242, Ria R1x24 22x24 (Rita) 22+24 R = 11.52 equivalent resistance between Ri R= Rit R2 = (1.5 +5.5) 52 R=172 I2 = YA I2 = 2:30 Amp Ta x 24 (2.30x29 24+ R) 22 +29 Ij = 1,20 Amp Tag = Pa-Ij = (2.30-1-20) Ang Strap Tinggit = 1.1 Army (as comment through 5.52 ²2.30 Amp (12) 1.20 Amp (11) 292) to 1. 10 Amp (124) (6) Now using node rele at point a Lg hf 124 Now, I a Amp ic 222

11 Using KVL in loop AEB C D Ag 1340(21) - V + 12 Ry=0 24124 +5.5 12 = 39V KHL in loop A EBFA, FRI- I 24 924 =0 24 124 = Using 111 22 11 12 124 11 = and, I2 = 11 + 129 = (1, 2 q + 224 Iza 23 124 ses from ean o 222 24 124 +5.5(33) 199= 39 24 124 +11.5 124 - 39 124 = Amp = 1.10 Amp Izq = 1.10 Amp from fio 12 I = 12x1.2 Amp 39 Amp 35.5 1 = 1.2 Amp egan n o, I 2 = 1, +229 = (12+1.1) Aug 1 gol from P2 = 2-3 Amp I = 1.20 Amp I2 = 2.30 Amp = 1.10 Amp In part ® are comme beef DBA up' answers