A proton (m = 1.67 x 10-27 kg) enters a region of space with velocity 10^j...
Hi guys, please help me answer this question and show me all the equations, and steps you used to solve it. Thanks ! d - A proton (m 1.67 x 10-22 kg) enters a region of space with velocity 10%j m/s. In this region an electric field -10%) N/C exists. Find the dis- tance the proton goes before stopping. d=?
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and a charge of q_p = 1.60 \times 10^{-19} ~Cq p =1.60×10 −19 C is moving through vacuum at a constant velocity of 10,000 ~m/s10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of | \vec{E} | = ∣ E ⃗ ∣=2.60e+3~N/C N/C . The region of uniform...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and a charge of q_p = 1.60 \times 10^{-19} ~Cq p =1.60×10 −19 C is moving through vacuum at a constant velocity of 10,000 ~m/s10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of | \vec{E} | = ∣ E ⃗ ∣=2.35e+3~N/C N/C . The region of uniform...
A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving through vacuum at a constant velocity of 10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E =3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How far (in meters) will the proton have been deflected towards the south by the...
In a vacuum, a proton (charge = +e, mass = 1.67 x 10-27 kg) is moving parallel to a uniform electric field that is directed along the +x axis (see figure below). The proton starts with a velocity of +5.10 x 104 m/s and accelerates in the same direction as the electric field, which has a value of +2.10 x 103 N/C. Find the velocity of the proton when its displacement is +2.0 mm from the starting point. à +x...
In a vacuum, a proton (charge = +e, mass = 1.67 x 10-27 kg) is moving parallel to a uniform electric field that is directed along the +x axis (see figure below). The proton starts with a velocity of +4.40 x 104 m/s and accelerates in the same direction as the electric field, which has a value of +7.90 x 103 N/C. Find the velocity of the proton when its displacement is +2.0 mm from the starting point. +2.0 mm...
In a vacuum, a proton (charge = +e, mass = 1.67 times 10^-27 kg) is moving parallel to a uniform electric field that is directed along the +x axis (see figure below). The proton starts with a velocity of +4.30 times 10^4 m/s and accelerates in the same direction as the electric field, which has a value of +5.70 times 10^3 N/C. Find the velocity of the proton when its displacement is +2.0 mm from the starting point. Number Units...
A proton (g = 1.6 X 10-19 C, m = 1.67 X 10-27 kg) moving with constant velocity enters a region containing a constant magnetic field that is directed along the z- axis at (x,y) = (0,0) as shown. The magnetic field extends for a distance D = 0.67 m in the x-direction. The proton leaves the field having a velocity vector (Vx, vy) = (2.6 X 105 m/s, 1.2 X 105 m/s). V ---D---- 1) What is v, the...
If a proton m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is released from rest at the + plate in the below electric field, what will be its speed at the-plate? 3 cm E = 5000 N/C
A proton (m, = 1.67 X 10-27 kg, qo=e= 1.60 X 10-19 C) and an alpha particle (me = 4m, 9a= 49p) start from rest at the same point in a region of uniform electric field E= 200 V/m. Each particle travels a distance of 4.0 cm in this field. (a) At that point, which particle has the higher kinetic energy, and what is this energy? (b) At that point, which particle is moving with the higher speed, and what...