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We are given the initial value y(0) = 2. Substituting this value and solving for L{y} gives the following result. sl{y} - y(0

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+ 51() – J10)+4 L1J) = 5 5L11)-9+463) asks Sly) +4 2ly)) sh Lloys+4) +2 3-5 st+2 bid= + (8-5)+4) $+4 - 1+2(3-5) (5.5) (514) -

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