Question

1. Consider a hydraulic system with two pistons. Piston 1 applies a force F, over area A, and piston 2 applies a force F over area Ay. If you double the force applied by piston 1 and reduce the area of piston 2 by a factor of 3, what is the new force in terms of the original force F? 2. A piston that is part of a hydraulic system has a surface area of 0.025 square meters. The hydraulic fluid pushes on the piston with a pressure of 20,000 pascals. What pressure pushes on another piston in the same system? 3. In a hydraulic system, a piston with a cross-sectional area of 21 square centimeters pushes on an incompressible liquid with a force of 38 newtons. The far end of the hydraulic pipe connects to a second piston with a cross-sectional surface area of 100 square centimeters. What is the force on the second piston?

Answer 1

1 According to Pascals law F2 Az = F22 A for new condition F = (2F). A2/3 = 2 FAZ 3 F - F2 = 32 pressure will be same p=20,000 Pa F2 = A FI - 100 cm? x 38 N 21 cm2 3800 N - 180.95 N 181N 181 N

According to pascal's Law pressure will be same at every where in liquid at same height.

Thanks for asking.