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132 Homework 3 Due Tuesday January 29 (if possible...) Read sections 10-1 through 10-5. Chapter 10 Questions: 2, Exercise 2: A circular suction cup with a radius of 4.50cm has one atmosphere pushing down on one side, a force F pulling up, and a vacuum underneath. What is force F required to cancel the force of the (one) atmosphere of pressure? (Ans, between 600 and 700N, or nearly 150 pounds. Its REALLY hard to pull two objects apart if you create a vacuum by doing it.) hapter 10 Problems: nonurionId suggest going with meters all the way.],
OLD meters the number 7:[Suppose a persons weight is evenly distributed over the four legs of a chair (person plus all way chair:82.0kg). The area of contact with the floor is 2.00 cm2 for each chair leg. Calculate the pressure on the floor for each chair leg, and compare that to the pressure of an elephant (mass of 5000.kg) standing on one foot (800.cm). Now compare to the pressure exerted under a 70.0kg ice skater standing on two skates which EACH have rectangular cross sections of 25.0cm by 0.400cm. Watch out that you really use WEIGHT and, to get the correct units for pressure, use Newtons per square METER, not square em or mm. Give your answer in Pascals d atmospheres.], 17 [Part a only. Just an application of the pressure depth relationl, Exercise 7: Look at Figure 10-6(a) with the car on a lift. To get a scale of what is what, assume the car and support piston have a mass of 1800kg and that the air pressure outside is 0.920 atmospheres. Finally, suppose the diameter cf the (circular) shaft of hydraulic oil under the car is 20.0cm. A) Adapt the discussion from class to figure out the pressure at the oil-piston interface right under the car. Hint: the pressure WOULD be 0.920 atmospheres except for the weight of the car, support-and-piston setup, which increases the pressure as we saw in class. B) Assume this pressure is the same at the Fin side and that the radius of the input piston is 0.750cm. What force must be exerted on the input side in order to hold the input piston in place (assuming negligible mass of this piston so that you have to exert all the necessary force- except for the 0.920 atm which is on this side also.) I get approximately 100N. OK. Im sure there are LOTS of more fun things in this chapter, but lets go to HEAT. Hopefully Ive given some problems like some of you need for the MCAT, and perhaps a basis for understanding fluid pressure in biological systems - which would involve nearly all the rest of Chapter 10. But hey , go for it if you need it. Later. Chapter 13, Here We Come! Chapter 13 Problems: (Not like you have to read ANY of Chapter 13 for these exercises in F f showing your work, use the equation on pagePlease answer exercise questions 2 & 7 and explain how you got the answers.
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Answer #1

Question 2

Force = pressure x area

Here, pressure = 1 atm = 1.01 × 10^5 N/m^2

Area = pi × r^2 = 3.14 ×(4.5 × 10^-2)^2 = 6.3585 × 10^-3 m^2

So, force = 1.01 × 10^5 × 6.3585 × 10^-3 = 642.2 N

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