Question

10

A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio pulse for each rotation of the star. The period of rotation is found by measuring the time between pulses. Suppose a pulsar has a period of rotation of T=0.0478s that is increasing at the rate of 488 x 10-8 (a) What is the pulsar's angular acceleration a ? (b) is constant, how many years from now will the pulsar stop rotating? (c) Suppose the pulser originated in a supernova explosion sen 932 years ago. Assuming constanta, find the initial T. (a) Number Units (b) Number Units (c) Number Units

Answer 1

solution- Given that - T = 0.04785 dT = 4.88810 *5/4" 20 T due (39 (a) The pulse aughlar speed is given by The pulse augular accleration is given by Derivation yields a = -21 dT substitute given values in the above formula dt dt T2 dt 4 • 88 x 158 C0.04787 GO X 60X24x365:25 -4.252707 4-252 8 10 12 rad 32 b? using kinetics of rotation, we will find out the time for pulsar to stop rotating. 1 - 10 tot = Ö - 27 - 4.252x10 12 - 27 -2 4.252x104 0-6478 => 131.4473-4.252x10-12+ 30. te 1314473 40252x10-12 = 3.094 1013 s=979x18y. t=979 X 103 years

) 2020 932 = 1088 y. The pulsar is originated in a Super nova eaplosion 1086 years ago. Then the initial period was 1058 0.04.26. Pane X 4-86X108 0477 S Ti=0.04775