Question

A capacitor consists of two 6.1-cm-diameter circular plates separated by 1.0 mm. The plates are charged to 140 V, then the battery is removed. (-8.85 x 102 c/(Nm) Part A How much energy is stored in the capacitor? Express your answer in joules. 190 ΑΣΦ Om ? Uc- J Submit Request Answer Part B How much work must be done to pull the plates apart to where the distance between them is 2.0 mm? Express your answer in joules VOTA he ? W- J Submit Best Answer

Answer 1

SOL 0=6.1cm o de 2mm the initial capacitance e' C = E. A d 8.8510*!? 2.148 6:03 104 3-aܨ ܐ ܐ 4 Te= 25.85 81012 f the final capacitance ! - Eo A d 8-85 x10 12x 3.148 (6-1)²x104 8 .4 2X10-3 C'= 12.9 2 81012F V = 140 2 2 cal the energy stored in capacitori c) U = I ev? x 25.8501012 (140) Tu= 0.253 4100 g (b) the final energy stored in Capacitor el y = 1 c'V² 12.92 X162 X(140) Tup = 0.126 X100 2 1 2 2

then work done is is equal to change in energy of capacitor لا - راز = د کنر (8.233 - 24/) = ب /2012701 - لا مال
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