1A) the equilibrium constant of reaction
Sr(s)+Mg24(ac)---><--- Sr24(ac)+Mg(s)
is 2.69X1012 at 25º C calculate the Eº of the cell formed by the half cells Sr / Sr2 + and Mg / Mg2 +
R= 8.314 J/k -mol
F= 96500 J/V- mol
1B)
Calculate the standard emf of a cell using the Ag / Ag1 + and Al / Al3 + half-cell reactions.
answers
A)0.86 V
B)2.46 V
C)-1.86 V
D)-0.86 V
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1A) the equilibrium constant of reaction
Sr(s)+Mg24(ac)---><---
Sr24(ac)+Mg(s)
is 2.69X1012 at 25º C calculate the Eº...
The equilibrium constant for the reaction Sr(s) + Mg2+(aq) ⇌ Sr2+(aq) + Mg(s) is 3.69 ×...
The equilibrium constant for the reaction Sr(s) + Mg2+(aq) ⇌ Sr2+(aq) + Mg(s) is 3.69 × 1017 at 25°C. Calculate E o for a cell made up of Sr / Sr2+ and Mg / Mg2+ half-cells. V
librium constant for the reaction Sr(s) + Mg (a)+ Mgo) is 2.69 × 1012 at 25°C....
librium constant for the reaction Sr(s) + Mg (a)+ Mgo) is 2.69 × 1012 at 25°C. Calculate E。for a cell nad 8.24 The equi се up of Str/Sr2 and MgMg2 half-cells, a cell
The equilibrium constant, K, for a redox reaction is related to the standard potential, Eº, by...
The equilibrium constant, K, for a redox reaction is related to the standard potential, Eº, by the equation In K = nFE° RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol · K), and T is the Kelvin temperature. Standard reduction potentials Reduction half-reaction E° (V) Ag+ (aq) + e +Ag(s) 0.80 Cu²+ (aq) + 2e + Cu(s) 0.34...
Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Fe+ (aq) + Cd(s)—...
Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Fe+ (aq) + Cd(s)— 2Fe2+ (aq) + Cd²+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant AGⓇ for this reaction would be than zero. Submit Answer Retry Entire Group 6 more group attempts remaining Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cu + (aq) - Cu(s)— 2Cu (aq) + Cu+...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
Review I Constants I Periodic Table The equilibrium constant, K, for a redox reaction is related...
Review I Constants I Periodic Table The equilibrium constant, K, for a redox reaction is related to the standard potential, E°, by the equation Standard reduction potentials nFE RT In K E° (V) Reduction half-reaction Agt(aq)eAg(s) Cu2+(aq)2eCu(s) 0.80 where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol - K) , and T is the Kelvin temperature. 0.34 Sn4t (aq)4eSn(s) 0.15...
librium constant for the reaction Sr(s) + Mg (a)+ Mgo) is 2.69 × 1012 at 25°C. Calculate E。for a cell nad 8.24 The equi се up of Str/Sr2 and MgMg2 half-cells, a cell
The equilibrium constant, K, for a redox reaction is related to the standard potential, Eº, by the equation In K = nFE° RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol · K), and T is the Kelvin temperature. Standard reduction potentials Reduction half-reaction E° (V) Ag+ (aq) + e +Ag(s) 0.80 Cu²+ (aq) + 2e + Cu(s) 0.34...
Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Fe+ (aq) + Cd(s)— 2Fe2+ (aq) + Cd²+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant AGⓇ for this reaction would be than zero. Submit Answer Retry Entire Group 6 more group attempts remaining Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cu + (aq) - Cu(s)— 2Cu (aq) + Cu+...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
Review I Constants I Periodic Table The equilibrium constant, K, for a redox reaction is related to the standard potential, E°, by the equation Standard reduction potentials nFE RT In K E° (V) Reduction half-reaction Agt(aq)eAg(s) Cu2+(aq)2eCu(s) 0.80 where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol - K) , and T is the Kelvin temperature. 0.34 Sn4t (aq)4eSn(s) 0.15...
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