solve the triangle
solve triangle
Given a = 10, A = 30°, and b = 24
Solve the triangle, given a=10,b=13, and angle A=25
degrees
3. Solve the triangle, given a = 10, b = 13, and ZA = 25°. (round answer to one decimal place.
Solve the triangle ABC, if the triangle exists. B = 30 degrees 48 ' a = 38.1 b = 31.2 Select the correct choice below and fill in the answer boxes within the choice. A. There is only 1 possible solution for the triangle. The measurements for the remaining angles A and C and side c are as follows. mangleAequals nothingdegrees nothingprime mangleCequals nothingdegrees nothingprime The length of side cequals nothing (Simplify your answer. Round to the nearest degree as...
1. (12pts) Solve the triangle AABC. a. Given A = 45°,b= V8, and c = 2 b. Given a = 10, A = 30°, and b = 24
Given a triangle with angle A = 93 degrees and sides a = 33 and b = 16. Find side c. c= Using the Law of Sines to solve the triangle if a = 13°,B= 23°, a = 20. Round to two decimal places. As in the text, (a, a), (B, b) and ( c) are angle-side opposite pairs. If no such triangle exists, enter DNE in each answer box. Preview degrees b= Preview Preview Due in 1 hours, 36...
Solve the triangle. b=10 inches a=26 inches c=24 inches (The figure is not to scale.) A= 0 (Type your answer in degrees. Round to one decimal place as needed.) Enter your answer in the answer box and then click Check Answer. parts Clear All Check Answer remaining
Solve for the triangle ABC if a = 30°, a = 10, b = 5 O B = 75°, y = 75°, c = 5.0 O Triangle does not exist O B = 10.12º, y = 139.88°, c = 11.0 O B = 14.480, y = 135.52°, c = 14.0 O B = 250, y = 125°, c = 18.0
solve the triangle A=
B=
C=
in degrees
13 С. 6 B А. 8
2. Solve Triangle ABC, given that B = 74'40', a = 8.92 in, c =6.43 in. Give angles in degrees and minutes. C *+P En
Based on the Oblique Triangle as shown below, solve for the following in feet or Degrees, Minutes, Seconds as required. Solve for A Given a = 143.56', b = 90.25' and c = 177.92' B a 53° 18' 11" 53° 56'43" 53° 29'44" 54° 17' 71" 50° 18' 14"