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Question 23 3 pts Reaction rates at various initial concentrations of reactants were measured at 900°C...
Sucrose, a sugar, decomposes in acidic solution to produce glucose and fructose. The reaction is first order in sucrose, and at 25 °C the rate constant is k = 3.60 x 10-3-1. If the initial concentration of sucrose is 0.050 M, what is the concentration after 2 days? O 0.042M 4.3 x 10-3M O 0.028 M 0.013 M
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.40 0.40 0.40 1.2×10−4 2 0.40 0.40 1.20 3.6×10−4 3 0.80 0.40 0.40 4.8×10−4 4 0.80 0.80 0.40 4.8×10−4 Rate law equation The rate of a chemical reaction depends on the concentrations of the reactants. For the general reaction between A and B, aA+bB⇌cC+dD The dependence of the...
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.40 0.40 0.40 1.2×10−4 2 0.40 0.40 1.20 3.6×10−4 3 0.80 0.40 0.40 4.8×10−4 4 0.80 0.80 0.40 4.8×10−4 Rate law equation The rate of a chemical reaction depends on the concentrations of the reactants. For the general reaction between Aand B, aA+bB⇌cC+dD The dependence of the reaction...
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. What is the reaction order with respect to B? Also, how do you find the value of the rate constant k for this reaction? Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.30 0.30 0.30 9.0×10−5 2 0.30 0.30 0.90 2.7×10−4 3 0.60 0.30 0.30 3.6×10−4 4 0.60 0.60 0.30 3.6×10−4
For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.30 0.30 0.30 9.0×10−5 2 0.30 0.30 0.90 2.7×10−4 3 0.60 0.30 0.30 3.6×10−4 4 0.60 0.60 0.30 3.6×10−4 What is the value of the rate constant k for this reaction?
For the reaction A+B+C→D+EA+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trials [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.20 0.20 0.20 6.0x10-5 2 0.20 0.20 0.60 1.8×10−4 3 0.40 0.20 0.20 2.4×10−4 4 0.40 0.40 0.20 2.4×10−4 Given the data calculated in Parts A, B, C, and D, determine the initial rate for a reaction that starts with 0.45 M of reagent A and 0.90 M...
s- (3 pts) The flowing rates have been an enzyme- catalyzed reaction at various substrate concentrations: Run no. 103 [S]M Rate, v/ (Ms') 2.41 3.33 4.78 6.17 7.41 9.52 0.0 12.5 0.4 0.6 4 2.0 4.0 a- From Line-Weaver double reciprocal plot, obtain and Mechaelis-Menten constant, max b- If the enzyme concentration is 1.00 x 10-11 M calculate kz.
Question 3 1 pts The rate constant, k, of the first order reaction A B +C is k = 8.62 x 10-35-1. If the initial concentration of A is 2.74 M, how long will it take for the concentration of A to fall below 0.32 M? Give your answer to one decimal place in MINUTES (do not input the units). For example, if your answer is 8.956 minutes, enter 9.0 Question 4 1 pts The rate constant, k, of the...
*Question Completion Status: a) For the reaction O2 (9) + 2NO(9) -... 2NO2 (g) Experiments were carried out to find out how the rate of the reaction depend on the concentrations of the reactants. The results were surrirarized in the following table. Experiment Initial Rate (mol/l.) 3.21 x 10 1 2 6.40 x 10 Initial Reactant Concentrations (mol/L) [0] [NO 1.10 x 10 1.30 x 10 2.20 x 100 1.30 x 100 1.10 x 10 2.60 x 10 1.30 x...
Question 22 2 pts The following reaction is first order in respect to CH3OH and first order in respect to HCI. With this in mind, what is the rate constant for the reaction? Be sure you choose the answer with the right units. CH2OH(aq) + HCl(aq) CH2Cl (aq) + HO (0) CH3OH HCI Initial Rate Reaction conc. conc. (M/s) 1 0.100 M 0.100 M 1.1 x 10-2 *conc = concentration 1.1 M-1 • 5:1 1.15-1 11 M-1.5-1 11 5-1 Question...