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3 pts Solve the problem. The distance d (in miles) that an observer can see on a clear day is approximated by d (h) = 20 Th.
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deas: 49 va yo When d (h) = 9.8 mi 49 va 9.8 yo = gad x 40 ug -ha (9.84 x yo yg Here Her eye sevil is (g. 8 x 4 4 feet Please

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