Question

5 pts Question 20 A Pt-204 atom (platinum-204) has a nucleus with 78 protons and an atomic mass of 203.980762 u. What is the nuclear binding energy per nucleon in this atom? 1.72 MeV 1603 MeV C 20.6 MeV 12.7 MeV 7.86 MeV Question 21 5 pts What is the DeBroglie wavelength of an electron with a kinetic energy of 50,000 eV? 6.59E-12 m 2.12E-12 m 4.42E-5 m 8.00E-15 m 5.48E-12 m

Answer 1

I'm very sorry to say that according to the HOMEWORKLIB RULES we are allowed to solve only first question. Please co-operate. Thankyou.

20. Number of Protons(P) = 78

Mass of protons(m_{​​​​​​p}) = 1.00783 amu

Number of Neutrons (N) = 204 - 78 = 126

Mass of neutrons(m_{​​​​​​n}) = 1.00867 amu

Mass of nucleous(m_{​​​​​​nucleous)} = 203.980762 amu

Mass Defect (∆M) = Pm_{​​​​p} + Nm_{​​​​​n} - m_{​​​​​​nucleous} = (78*1.00783) + (126*1.00867) - 203.980762 = 1.722398 amu

Binding Energy = ∆M × 931.5 MeV = 1604.4 MeV

Binding Energy per Nucleons = Binding Energy/204 = 7.86 MeV