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26. Steel studs are to be used to support a gypsum drywall. If the wall is 325.33 feet long and the spacing is 16 OC, How ma
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Answer:

26.

Wall Length = 325.33 ft

Spacing of Studs = 16 "

Total no. of studs required =   \frac{Wall Length}{Spaacing of studs}

=\frac{325.33 * 12"_{/ft}}{16"}

= 244 Nos.

27.

Flat Roof ; L = 120 ft & B =50ft

A = L x B = 120 x 50 = 6000 Sq. ft.

So, total 6000 Square feet of roofing material required.

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