At a Chinese restaurant, dinner for 8 people consists of 3 items from column A, 4 items from column B and 3 items from column C. If columns A, B and C have 5, 7 and 6 items respectively how many different dinner combinations are possible?
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different dinner combinations = 5C3 * 7C4 * 6C3 = 7000
answer = 7000 different combination possible
At a Chinese restaurant, dinner for 8 people consists of 3 items from column A, 4...
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(1) (5 pts) How many ways can you permute the letters in BANANA? (2) (5 pts) At a Chinese restaurant, dinner for 8 people consists of 3 items from column A, 4 items from column B and 3 items from column C. If columns A, B and C have 5, 7 and 6 items respectively how many different dinner combinations are possible?
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