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5. Use the spectrochemical series and the color of the following complex ions to write the...
oct Original Color (M2+ H20) Complex Color (M2+/ Ligand) de calidad superior de haute qualité CI- Complex ion Formula Effect of H20 Cu2+ Complex ions: [Cucl.]2- changed BLUE ZEHIO NH3 dark en BLUE SCN- green Ni2+ Complex ions: CI- NH3 GREEN Ligand Effect of OH- green BLUE no change. bue I (NH) no change. Changed to (percip). cloudy/lignt bowe dariple ese (Haiche, no change. no change BLUE line neon [Cursen) i no change. Shangcaute changed to peras) Ligand cloudy out...
oct Original Color (M2+ H20) Complex Color (M2+/ Ligand) de calidad superior de haute qualité CI- Complex ion Formula Effect of H20 Cu2+ Complex ions: [Cucl.]2- changed BLUE ZEHIO NH3 dark en BLUE SCN- green Ni2+ Complex ions: CI- NH3 GREEN Ligand Effect of OH- green BLUE no change. bue I (NH) no change. Changed to (percip). cloudy/lignt bowe dariple ese (Haiche, no change. no change BLUE line neon [Cursen) i no change. Shangcaute changed to peras) Ligand cloudy out...
6. Draw orbital-energy splitting diagrams and use the spectrochemical series to show the orbital occupancy for each of the following (assuming that H2O is a weak-field ligand): [Мось) INi(H2O)e] [Ni(CN)J2
The spectrochemical series is < Br<< Cl<F-<OH" <H2O <NH3 <en <NO2- < CN- The complex [Ni(Cl)c] is green and the complex [Ni(en)]2+ is violet, where en corresponds to the ethylenediamine ligand. The reason for the difference in the color of these complexes is: Select one: A. The chloride ligand is green, and the ethylenediamine ligand is violet. B. The difference in the coordination numbers of the chloride complex and the en complex. C. The difference in the oxidation states of...
oct Original Color (M2+ H20) Complex Color (M2+/ Ligand) de calidad superior de haute qualité CI- Complex ion Formula Effect of H20 Cu2+ Complex ions: [Cucl.]2- changed BLUE ZEHIO NH3 dark en BLUE SCN- green Ni2+ Complex ions: CI- NH3 GREEN Ligand Effect of OH- green BLUE no change. bue I (NH) no change. Changed to (percip). cloudy/lignt bowe dariple ese (Haiche, no change. no change BLUE line neon [Cursen) i no change. Shangcaute changed to peras) Ligand cloudy out...
oct Original Color (M2+ H20) Complex Color (M2+/ Ligand) de calidad superior de haute qualité CI- Complex ion Formula Effect of H20 Cu2+ Complex ions: [Cucl.]2- changed BLUE ZEHIO NH3 dark en BLUE SCN- green Ni2+ Complex ions: CI- NH3 GREEN Ligand Effect of OH- green BLUE no change. bue I (NH) no change. Changed to (percip). cloudy/lignt bowe dariple ese (Haiche, no change. no change BLUE line neon [Cursen) i no change. Shangcaute changed to peras) Ligand cloudy out...
The transition metal ion, Fe(III), can form octahedral or tetrahedral complexes depending on the ligand it binds to. (a) (i) [Fe(CN)6]3- is a strong field octahedral complex of Fe(III). Draw a labelled orbital energy level diagram that shows both the splitting of the d-orbitals and their electron occupancy in [Fe(CN)6]. (3 marks) (ii) Fe(III) can also form tetrahedral complexes, most of which are weak field. Draw a labelled orbital energy level diagram that shows both the splitting of the d-orbitals...
Date: 1117 mework 10 - Ch. 21-23 A) CN B)NO c)r D) CO Name: E ) en 24. Place the ligands, CN-, Br., H2O, and OH-in order from least to greatest according ability to split the d orbital energy level. A) CN-, OH, H2O, Br- C) Br,H20, CN-, OH- B) Br., OH, H2O, CN- D) None of the above 25. The charge on the central metal ion in (Cr(NH3)(CO3)2+ is A)-1. B) 0. C) 1. D) 3. E) 5 26....
can anyone please confirm my answers for 5&6? And can you explain how to fill in the electrons for 7? Please and Thank you. 5. The values of A, for some coordination complexes are given below. (a) [Fe(ox)) --- 14,100 cm-1 (ox-oxalato ligand-----weak ligand] (b) [Fe(CN).-----35,000 cm ©) [Fe(CN)6]* -----33,800 cm (1) Explain reason(s) why A. of complex (a) and (b) are different (ii) Explain reason(s) why 4, of complex (b) and (c) are different 6. Answer the following questions...
Use the following electrochemical series: CN -1 > NO2-1 > en > NH3 > H2O > OH -1 > F -1 > Cl -1 > Br -1 > I -1 Given compound: [Mn(en)3]+3 For octahedral field splitting diagrams, outline in detail how you determine the following: a) neutral metal's electron configuration b) ion's electron configuration c) the number of d electrons in the ion d) drawing the splitting pattern, labeling the orbitals in the splitting pattern, the filling of electrons,...