CALCULATE THE x2 Statistics and use it to...
Solve using Excel:
ACTUAL | |||||||
Frequently | Rarely | Never | Total | ||||
Above 30 | 52 | 94 | 54 | 200 | |||
30 or younger | 47 | 52 | 21 | 120 | |||
Total | 99 | 146 | 75 | 320 | |||
EXPECTED | |||||||
Frequently | Rarely | Never | FORMULA FOR EXPECTED VALUE | ||||
Above 30 | 61.88 | 91.25 | 46.88 | =(B$5*$E3)/$E$5 | =(C$5*$E3)/$E$5 | =(D$5*$E3)/$E$5 | |
30 or younger | 37.13 | 54.75 | 28.13 | =(B$5*$E4)/$E$5 | =(C$5*$E4)/$E$5 | =(D$5*$E4)/$E$5 | |
CHI-SQUARE | |||||||
Frequently | Rarely | Never | FORMULA FOR CHI-SQUARE | ||||
Above 30 | 1.58 | 0.08 | 1.08 | =(B3-B9)^2/B9 | =(C3-C9)^2/C9 | =(D3-D9)^2/D9 | |
30 or younger | 2.63 | 0.14 | 1.81 | =(B4-B10)^2/B10 | =(C4-C10)^2/C10 | =(D4-D10)^2/D10 | |
Test statistic | 7.31 | =SUM(B14:D15) | |||||
Critical value | 5.99 | =CHISQ.INV.RT(0.05,2) |
H0: Participant's age is independent of whether they shop online
H1: Participant's age is not independent of whether they shop online
Test statistic = 7.31
Degrees of freedom: df = (rows-1)*(columns-1) = (2-1)*(3-1) =2, Level of significance = 0.05
Critical value (Using Excel function CHISQ.INV.RT(probability, df)) = CHISQ.INV.RT(0.05,2) = 5.99
Since test statistic is greater than critical value, we reject the null hypothesis.
Conclusion: Participant's age is not independent of whether they shop online.
CALCULATE THE x2 Statistics and use it to... A survey asked participants whether they shop online...
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