Question

Please provide a descriptive explanation behind the work used to solve the problem

Problem 10-Reflection & refraction: As shown below, a laser beam is sent into the system from the lower left at an angle of 20°. If it hits the screen at a height of 8.5 cm, what is the refractive index of the unknown material? n = 1 n = ? n = 1 8.5 cm =20° 10 cm 5 cm 10 cm

Answer 1

0,- 20, n=1 n=1 fos ais. Let, n' be sefractive index of medium. Oz h 0 ha Now, Thi hio fand. 11 A loom sem loon on, h = 10x tano, his lox dan 20 = 3064 cm Height of Lifting point point at screen, h=8.5 En Now, at sight region also, hosizontal distance coresed loem and angle of sefsaction refracted say from medium is Here also restical distance core resed is hi fan O.. O, = 209, So, lo . hi on, - hóa 10x fan 20 hi 3.64 cm. So, Height of emergent say from from medium ha= hah! hrh,. (3-5-3-64) hea 4-86em. 11 СП. OM, sor Inside mede medium restical distance coresed, Aha harh,= (4.86 3.64) em. Aha 1-22 cm. on,

Horizontal distance d=5cm. 5 So fan Og = 1.22 Ah d on, A fan' ( 122/5) 13.71 on, Og Now using Snell's Law n sincha n'sino O on, n'a nsino, sind, xsin 20 sin (13.71) on, ba lo 14 ic Refractive index of the medium n'=1-44.