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Question 31 7.5 pts Determine AG ºrxn at 25°C using the following information CCI (9) →...
Question 31 7.5 pts Determine AG rxn at 25°C using the following information CCI (9) → C (s, graphite) + 2Cl2 (9) AH°= +95.7 kJ; AS = +142.2 J/K +53.3 kJ 0 -348 kJ +440 kJ +28.4 kJ 0-58.3 kJ
The reaction CCl4--> C(graphite) + 2Cl2 has delta H= +95.7 kJ and delta S= +142.2 J/K at 25 degrees C. Calculate delta G.
Consider the reaction at 298 K. C(graphite) + 2Cl2(8) — CCI (1) AH° = -139 kJ Calculate the quantities. ASsys = J/K S TOOLS A TOOLS x102 ASsurr = asyr = O JK J/K ASuniy = Asuniv = UK J/K
9) Using the information given calculate, AH, AS and AG at 25°C (remember, for a reaction calculated using the relationship: AH = AH° reaction = nАHºf(products) - EnАHºt(reactants). PAY ATTENTION TO UNITS AND SIGN PC13(g) + Cl2 (g) → PCls(g) AHºt(kJ/mol) -287 O -374.9 (why is AHºt = 0 for Cl2?) Sºt (J/K) 311.67 223.1 364.47
Calculate AG for the following reaction at 25°C. 2 Ca(s) + O2(g) → 2 Ca(s) (J/K mol) Substance AH (kJ/mol AG (kJ/mol) Ca(s) Ca2+(aq) CaO(s) Ca(OH)2(5) CaF2(5) CaCl(s) O(g) 028) O3(aq) Oz(8) -542.96 -635.6 -986.6 -1,214.6 -794.96 249.4 -553.0 -604.2 -896.8 -1,161.9 -750.19 230.1 41.6 -55.2 39.8 83.4 68.87 113.8 160.95 205.0 110.88 237.6 -12.09 142.2 16.3 163.4
estion 17 of 25 > Given the information A+B 2D C D AH' = -629.4 kJ AH = 464.0 kJ AS = 327.0 J/K AS' = -147.0 J/K calculate AG at 298 K for the reaction A+B - 20 1 AG" = kJ 30 A w 09 S For a particular reaction, AH = -111.4 kJ/mol and AS = -25.0 J/(molK). Calculate AG for this reaction at 298 K. AG = -14.83 KJ/mo Incorrect What can be said about the...
Using provided data, determine AG* (in kJ) for the following reaction. 2036) ++3026) AH,(kJ/mol) S /mol) Ozle) 205.0 Ole) 143 238.82 Question 11 2 pts Use the provided information to determine the equilibrium constant at 298 K for the reaction given 2NO26) N204(8) 4 AH® (kJ/mol) 5° (J/molk) NO2(g) 33.2 239.9 N2048) 9.16 304.3 Equilibrium Constant - (Select) x 10 (Select)
(9) A spontaneous process has the change of free energy (a) AG>0 (c) AG = 0 (b) AG <O (d) AH>0 and AS <O (10) A chemical reaction has AH = 10 kJ. AS = 50 J/K at temperature T = 300 K. the reaction AG = J. (a) 5000 (b) -5000 (c) 10000 (d) 50 (11) For reaction: Ag (s) + 2 Cl2 (g) Ag° (aq) +CI (aq), the standard free energy of formation: AGf° (Ag*) = 77.1 kJ/mol,...
Question 39 What is the value of AH° for this reaction at 25°C ? + C(s) + H20(g) ---> CO(g) H2(9) AG° = + 91.2 kJ/mole AS° J/K mole 91 kJ/mole O 40 kJ/mole 131 kJ/mole 226 kJ/mole A Moving to another question will save this response.
AG,O (25°C kJ/mol) ДнР (25°C kJ/mol) So Substance (25°C J/mol-K) NaNO, (s) -467.9 -367.0 116.5 NaNO2 (s) -358.7 -284.6 103.8 Cl2O (g) CI2OS (g) PbO (s) 80.3 97.9 266.2 -212.5 -198.3 309.8 -217.32 -187.89 68.7 CI2CRO2 (I) CI2CRO2 (g) -579.5 -510.8 221.8 -538.1 -501.6 329.8 Compute the AH°, AG°, and AS° for the reaction given below at two temperatures: 298 K and 315 K. PbCl2 (s)3NaNO2(s) PbO(s)NaNO3(s) +2NO(g) +2NaCl(s) At 298 K kJ ΔΗ' is AG° is kJ J/K AS...