Question

A girl slides down a snowy hill on an inflated tube sled where she collides with a boy who is stationary in another tube sled. After the collision the girl moves off at an angle θ1 = 10 degrees from her original direction of motion and the boy moves off at an angle θ2 = 40 degrees. The girl and her sled have half the mass of the boy and his sled. After the collision, what is the ratio of the boy's speed to the girl's speed?

Answer 1

Answer 2

V sino, u bo vieno At Rest mi &vices o Girl (mi) m2 VO2 Va Cos02 boy ling) + Na Vg sino Apply momentum conservation along x-axis. mivi coso , & mava Cos 02 m, u Here, my m2 and miam 2 mu mv, cus 10' +2m va cos you 0.985v1 + 1.5382 Similarly, apply momentum conservation along y-axis. mivi mivisino, & masing2 = 0 Sin ma Vasino mv, sin lo - 2m vg sin you V = sin lo & sinuo - 01135 n Vg VI 0.14