Question

A bowling ball (mass:6.5 kg) is thrown down a bowling alley with a speed of 8 m/s. where it has an off center collision with a bowling pin (mass: 1.5 kg). After the collision, the bowling ball moves off to the right of the original path of motion with a reduced speed of 6.2 m/s at an angle of 11.3 degrees as shown, while the bowling pin is deflected to an angle of 32.3 degrees to the left of the original path of motion. What will be the speed of the pin immediately after the collision? a. 9.8 m/s b. 6.3 m/s c. 12.8 m/s d. 9.1 m/s e. 16.3 m/s

Answer 1

Conserving momentum along the original direction of motion

$6.5*8=6.5*6.2*\cos11.3\degree+1.5*v*\cos32.3\degree$

Speed of pin immediately after collision $v=\frac{6.5*8-6.5*6.2*\cos11.3\degree}{1.5*\cos32.3\degree}=9.84\,m/s$

Hence answer is a. 9.8 m/s