Question

Billiard ball A of mass mA = 0.130 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.140 kg . As a result of the collision, ball A is deflected off at an angle of 27.5 ∘ with a speed vA1 = 2.25 m/s .

a.) Taking the x axis to be the original direction of motion of ball A, write down the equation expressing the conservation of momentum for the components in the x direction. Assume the velocity of ball B after collision is vB1. Express your answer symbolically in terms of the variables mA, mB, vA, vA1, vB1, θA, and θB.

b.) Write down the equation expressing the conservation of momentum for the components in the y direction. Express your answer symbolically in terms of the variables mA, mB, vA, vA1, vB1, θA, and θB.

Answer 1

@ Apply Conservation of momentum along namis MA VA AMB VB = MA VAGOA +mo BOB VB=0 MAVA - MAY COS O At mave, Cosob (6 Apply conservationg momentions Dong yam's 0 +0= m , SIMOA - MB VB, sino MAVA, SingA = MBB, SimoB