an object = 10.4cm high and placed 31.9cm infront of a diverging lens which has a...
A 0.49 cm high object is placed 8.5 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image?
A 0.44 cm high object is placed 8.4 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image?
An object of height 2.8 cm is placed 27 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length.Part (a) Find the location of the final image, in centimeters beyond the converging lens. Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
Consider a diverging lens of focal length f--20 cm and a virtual object placed 30 cm from the lens. Find the image distance q in centimeters. You may wish to complete this ray diagram Pick 10.0, -10.0, -50.0, -60.O, Consider a diverging lens of focal length f--20 cm and a virtual object placed 30 cm from the lens. Find the image distance q in centimeters. You may wish to complete this ray diagram Pick 10.0, -10.0, -50.0, -60.O,
An object is placed 16.4 m infront of a converging lens of focal lenght f1=40 cm. On the other side of the lens, there is a diverging lens of focal lenght f2=4 cm, seperated from the first lens by a distance of 36.9 cm. A) Where if the final image formed? b) What is the magnification and what is the angular magnification and how does the angular magnigifcation compare to the telescipe formula? C) Support your conclusion by drawing an...
2) A diverging lens is placed 20. cm away from an object, 80. cm from the diverging lens is a converging lens whose focal length is 25 cm. 35. cm from the converging lens is a screen showing an image of the object. a) What is the focal length of the diverging lens? f = 25. cm o *20. cm → 80. cm + 35 cm → b) What type of image is it? Circle one Real or Virtual c)...
An object is placed 32.0 cm to the left of a diverging lens with a focal length of -20.0 cm. A converging lens of focal length of 32.0 cm is placed a distance d to the right of the diverging lens. Find the distance d that the final image is at infinity. ______cm
The distance between an object and its image formed by a diverging lens is 46.9 cm. The focal length of the lens is -244.2 cm. (a) Find the image distance. (b) Find the object distance. An object is 20 cm in front of a diverging lens that has a focal length of -13 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 1.0?
A diverging lens has a focal length of -30.0 cm. An object is placed 20.0 cm in front of this lens. Calculate the image distance.
A 0.49 cm high object is placed 8.8 cm in front of a diverging lens whose focal length is -7.5 cm. What is the height of the image? 405cm Subet Arowe Incorrect. Tries 6/20 Previous Tries Post Discussion Send Feedback