A diverging lens has a focal length of -30.0 cm. An object is placed 20.0 cm in front of this lens. Calculate the image distance.
1/o + 1/i = 1/f
i = 1/(1/f - 1/o) = 1/(1/-30 - 1/20) = -12 cm
so the image is 12 cm in front of the lens
(b) m = -(i/o) = -(-12/20) = 0.6
A diverging lens has a focal length of -30.0 cm. An object is placed 20.0 cm...
A diverging lens of focal length –30.0 cm is placed 25.0 cm behind a converging lens of focal length 60.0 cm. A real, upright object of height 2.00 cm is placed 20.0 cm in front of the converging lens. (a) Determine the location of the final image. (Clearly state the location of the final image.) (b) Determine the size and the nature of the final image.
An object is placed 32.0 cm to the left of a diverging lens with a focal length of -20.0 cm. A converging lens of focal length of 32.0 cm is placed a distance d to the right of the diverging lens. Find the distance d that the final image is at infinity. ______cm
A diverging lens has a focal length that has a magnitude of 35.0 cm. An object is placed 20.0 cm in front of this lens. Calculate the magnification.
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An object is 17 cm in front of a diverging lens that has a focal length of -9.0 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.3? Number i ! Units cm