2nd flipflop will operate only when ClrN input is 1, thus when ClrN is 1, clock will be +ve edge triggered.
at initial:
Q2 = 0, D2 = 0
Q2' = 0, D2=0. hence Q2 =1
at the 4 +ve edge, when ClrN is 1:
D2=0, Q2'=0 and Q2 =1
Therefore, drawing the timing diagram from above results:
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Please give me
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