The R and P genes are 7 map units apart. RR pp is crossed to rr...
The R and P genes are 7 map units apart. RR pp is crossed to rr PP to make an F1 generation. List all possible gametes that will be produced by an F1 individual and the proportion of each type of gamete.
Homework Answers
The F1 genotype is Rp/rP which is obtained by the cross between the RRpp and rrPP parents. This F1 will produce the gametes: RP, Rp, rP and rp. Among these gametes, Rp and rP are the non recombinant gametes and RP and rp are the recombinant gametes. As the two alleles are separated by a 7 map units distance, it means that the recombinant will occur at 7% of the total offspring. Hence the proportion of formation of recombinant gametes RP and rp is 3.5:3.5 each. The proportion of formation of the parental gametes is 93% and hence the other two gametes will be produced in 46.5:46.5. hence the proportion in which the gametes are produced is - Rp:rP:RP:rp = 46.5 : 46.5 : 3.5 : 3.5.
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2. Two particular genes are linked and 14 map units apart. A GBIGB individual is mated...
2. Two particular genes are linked and 14 map units apart. A GBIGB individual is mated with a gblgb individual. a) Show the genotype of an FI offspring demonstrating linkage. b) What gametes can the Fl produce AND in what frequency? If the F1 generation mate amongst themselves, what is the frequency of GGbh F2 offspring? (show your work) c)
The P and Q genes of a plant are 20 m.u. apart. A PP QQ and...
The P and Q genes of a plant are 20 m.u. apart. A PP QQ and a pp qq individual cross, and the F1 cross with each other to produce the F2. The P and p, and Q and q alleles are completely dominant and recessive, and there are no interactions between genes P and Q. What phenotypic ratio would you expect in the F2?
In flamingos, genes A and B are known to be 21 map units apart on chromosome...
In flamingos, genes A and B are known to be 21 map units apart on chromosome #5. You mate an AA:BB male with an aa:bb female to produce F1 flamingos. a. What gametes will be made by these F1 individuals and in what proportions? b. When the F1's are bred to each other, they produce a total of 276 offspring. How many of these offspring would you predict should have the genotype Aa:BB?
Consider an individual with the genotype Ab/aB (below). The A and B genes are 27 map...
Consider an individual with the genotype Ab/aB (below). The A and B genes are 27 map units apart. Given this information, indicate the correct genotypes, and respective corresponding expected frequencies, for ALL possible gametes that can be produced by this individual during meiosis.
Explain why two genes 50 or more map units apart on a genetic map can only...
Explain why two genes 50 or more map units apart on a genetic map can only result in a maximum of 50% recombinant gametes in two point cross. To answer this, ask yourself what percentage of recombinant gametes would result if the probability of crossing over in a tetrad involving these genes were 100%, as it would be if the two genes are 50 or more map units apart.
what is the crossover percentage between two genes that are 10 map units apart 2. (25...
what is the crossover percentage between two genes that are 10
map units apart
2. (25 points) In a monohybrid, the phenotype of the F2 generation will follow a ratio of In a dihybrid, the phenotype of the F2 generation will follow a ratio of When performing a chi-square analysis, the cutoff p value is- The degree of freedom (df) for a monohybrid and the degree of freedom for dihybrid is The formula to calculate the chi-square is 3. 25...
27. An individual has the following genotype. Gene loci (A) and (B) are 15 map units...
27. An individual has the following genotype. Gene loci (A) and (B) are 15 map units apart, which determines their probability of recombination. 1) Indicate all the possible gametes that this individual can produce (with crossing over), 2) Label the gametes that are recombinant and non- recombinant. 3) Calculate the recombination frequency of the recombinant and non-recombinant gametes. The genes are not COMPLETELY linked. 28. Now imagine the genes are completed linked in #27. 1) What are all possible gametes?
please solve qs12-23 and include explanations thanks A wild-type trihybrid soybean plant Phenotype Number is crossed...
please solve qs12-23 and include explanations thanks
A wild-type trihybrid soybean plant Phenotype Number is crossed to a pure-breeding Pale 648 soybean plant with the recessive Pale, oval phenotypes pale leaf (), oval seed Pale, short 10 (r), and short height (t). The results Pale, oval, short 102 of the three-point test cross are Oval shown in the table. Traits not listed Oval, short 618 are wild-type. Short 84 Wild type 98 1. True False The phenotypes 1630 listed in...
Genes A and B are linked and 32 map units apart (A is dominant over a,...
Genes A and B are linked and 32 map units apart (A is dominant over a, and B is dominant over b). If an Ab/aB heterozygote is test-crossed and you look at 100 offspring, how many offspring recessive for both phenotypes do you expect? Answer:
3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We...
3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We will use this cross to determine the ratios of phenotypes in the F2 generation when there are two genes involved. 3.1) Use the following symbols to write out the cross: Male: 3 Female: 9 Dark body color (ebony) = e Wild-type body color: E or E+ Rudimentary wings- (vestigial wings= v) Wild-type wings: V or V+ 3.2) What would the cross look like if...
2. Two particular genes are linked and 14 map units apart. A GBIGB individual is mated with a gblgb individual. a) Show the genotype of an FI offspring demonstrating linkage. b) What gametes can the Fl produce AND in what frequency? If the F1 generation mate amongst themselves, what is the frequency of GGbh F2 offspring? (show your work) c)
Consider an individual with the genotype Ab/aB (below). The A and B genes are 27 map units apart. Given this information, indicate the correct genotypes, and respective corresponding expected frequencies, for ALL possible gametes that can be produced by this individual during meiosis.
what is the crossover percentage between two genes that are 10
map units apart
2. (25 points) In a monohybrid, the phenotype of the F2 generation will follow a ratio of In a dihybrid, the phenotype of the F2 generation will follow a ratio of When performing a chi-square analysis, the cutoff p value is- The degree of freedom (df) for a monohybrid and the degree of freedom for dihybrid is The formula to calculate the chi-square is 3. 25...
27. An individual has the following genotype. Gene loci (A) and (B) are 15 map units apart, which determines their probability of recombination. 1) Indicate all the possible gametes that this individual can produce (with crossing over), 2) Label the gametes that are recombinant and non- recombinant. 3) Calculate the recombination frequency of the recombinant and non-recombinant gametes. The genes are not COMPLETELY linked. 28. Now imagine the genes are completed linked in #27. 1) What are all possible gametes?
please solve qs12-23 and include explanations thanks
A wild-type trihybrid soybean plant Phenotype Number is crossed to a pure-breeding Pale 648 soybean plant with the recessive Pale, oval phenotypes pale leaf (), oval seed Pale, short 10 (r), and short height (t). The results Pale, oval, short 102 of the three-point test cross are Oval shown in the table. Traits not listed Oval, short 618 are wild-type. Short 84 Wild type 98 1. True False The phenotypes 1630 listed in...
Genes A and B are linked and 32 map units apart (A is dominant over a, and B is dominant over b). If an Ab/aB heterozygote is test-crossed and you look at 100 offspring, how many offspring recessive for both phenotypes do you expect? Answer:
3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We will use this cross to determine the ratios of phenotypes in the F2 generation when there are two genes involved. 3.1) Use the following symbols to write out the cross: Male: 3 Female: 9 Dark body color (ebony) = e Wild-type body color: E or E+ Rudimentary wings- (vestigial wings= v) Wild-type wings: V or V+ 3.2) What would the cross look like if...
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