Question

Find the tension in cable. The mass of the beam is 40 kg. 200 3 m **2m+ -2 m → 50 kg

Answer 1

Cable O = 20° mass of beam (m)= 40kg mass of block (M) = 50kg T Tsino take, g 9.8 m/s? Troso 209 A Find, Tension (T) in the -3m- -2.5m am cable. Mg = 50141 = M mg Let, Tension in the cable is" T” It has two components - ci Vertical component = Tsino Tsin 20 (ii) Horizontal component - Tloso Tos 20° The beam has mass of 40 kg, so, a grivity force "mg' will acted on cenfroid of beam le 215m from point A. 20 0, Similarly block applies the gravity force (Mg). Since, The whole system is in equilibrium Hence moment about “A” will be zero. ΣΜΑ= (moment about point A). Take clockwise positive. mgx 2.5 + Mgx 5 - TSin 20% 3=0 (40x9.0x2.5)+ ( 30x9.8*5) = T x 0.342x3 900 + 2450 = 1.03 T T = 3342.88 N ANSWER

We know that,

Moment (M) = force x perpendicular distance,

The horizontal component of tension (T) will not take part in the moment because perpendicular distance is zero.