Question
need help solving this problem. show work so i can understand please.

6. At 25°C, a steel rod is 2 cm in diameter. It is to fit a hollow steel ring of diameter 1.995 cm. What temperature should t
0 0
Add a comment Improve this question Transcribed image text
Answer #1

AA= B Ao OT in area ДА → change intial Area Ao ot change in tempreture B Constant for metal heat metal it it start expending:

Add a comment
Know the answer?
Add Answer to:
need help solving this problem. show work so i can understand please. 6. At 25°C, a...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Chapter 18, Problem 015

    A steel rod is 3.430 cm in diameter at 23.00°C. A brass ring has an interior diameter of 3.423 cm at 23.00°C. At what common temperature will the ring just slide onto the rod? The linear expansion coefficient of steel is 11.00 × 10-6 1/C°. The linear expansion coefficient of brass is 19.00 × 10-6 1/C°.

  • PLEASE SHOW ALL YOUR WORK AND EXPLAIN YOUR STEPS. THANK YOU! 1 Thermal Expansion A steel...

    PLEASE SHOW ALL YOUR WORK AND EXPLAIN YOUR STEPS. THANK YOU! 1 Thermal Expansion A steel rod is 3.000 cm in diameter at 25 °C. A brass ring has an inner diameter of 2.902 ㎝ at 25。C. At what common tempernture will the ring just fit outo the srod? o c The coefficient of linear expansion of brass is 19.10-6 per °c.

  • A steel rod is 3.418 cm in diameter at 26.00°C. A brass ring has an interior...

    A steel rod is 3.418 cm in diameter at 26.00°C. A brass ring has an interior diameter of 3.410 cm at 26.00°C. At what common temperature will the ring just slide onto the rod? The linear expansion coefficient of steel is 11.00 × 10-6 1/C°. The linear expansion coefficient of brass is 19.00 × 10-6 1/C°.

  • A steel rod is 2.855 cm in diameter at 20.00°C. A brass ring has an interior...

    A steel rod is 2.855 cm in diameter at 20.00°C. A brass ring has an interior diameter of 2.852 cm at 20.00°C. At what common temperature will the ring just slide onto the rod? The linear expansion coefficient of steel is 11.00 × 10-6 1/C°. The linear expansion coefficient of brass is 19.00 × 10-6 1/C°.

  • A steel rod is 3.311 cm in diameter at 27.00°C. A brass ring has an interior...

    A steel rod is 3.311 cm in diameter at 27.00°C. A brass ring has an interior diameter of 3.307 cm at 27.00°C. At what common temperature will the ring just slide onto the rod? The linear expansion coefficient of steel is 11.00 × 10-6 1/C°. The linear expansion coefficient of brass is 19.00 × 10-6 1/C°.

  • At 20∘C, the hole in an aluminum ring is 2.700 cm in diameter. You need to...

    At 20∘C, the hole in an aluminum ring is 2.700 cm in diameter. You need to slip this ring over a steel shaft that has a room-temperature diameter of 2.707 cm . To what common temperature should the ring and the shaft be heated so that the ring will just fit onto the shaft? Coefficients of linear thermal expansion of steel and aluminum are 12×10−6 K−1 and 23×10−6 K−1 respectively.

  • At 20∘C, the hole in an aluminum ring is 2.300 cm in diameter. You need to...

    At 20∘C, the hole in an aluminum ring is 2.300 cm in diameter. You need to slip this ring over a steel shaft that has a room-temperature diameter of 2.306 cm .To what common temperature should the ring and the shaft be heated so that the ring will just fit onto the shaft? Coefficients of linear thermal expansion of steel and aluminum are 12×10−6 K−1 and 23×10−6 K−1 respectively.

  • Please I need answers to these questions, thanks. brass ball gets so that it gets stuck...

    Please I need answers to these questions, thanks. brass ball gets so that it gets stuck in the ring. I've measured a similar piece of equipment. At room temperature (23 °C) the diameter of the ball is 1.90 cm and the inner diameter of the ring is 1.92 cm. How hot does the ball have to get in order for the ball to just get stuck? Hint: think of the diameter of the ball as a linear dimension, and find...

  • please show me a sep wise solution for these problem as i am trying to learn...

    please show me a sep wise solution for these problem as i am trying to learn from your solution. if you cant or you answer partially dont answer please. Question 4 (4 pts): A thin ring made of iron has an inner diameter of 1.00 cm at room temperature (25.0 C), but it needs to fit over a rod that is 1.05 cm in diameter. What you should do to the ring? Note that the coefficient of linear expansion of...

  • Hi I am working on the group work I need help with and a little explanation...

    Hi I am working on the group work I need help with and a little explanation with it that will help a lot. Tools View GW1 Ch 16 (Protected View)-Word (P OTECTED VIEW Be careful-files from the Internet can contain viruses. Unless you need to edit, it's safer to stay in Protected V Group Work: Ch. 16 1. A pressure of 10 mm Hg is measured using a constant-volume gas thermometer at a temperature of 50°C. What is the pressure...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT