Question

Y Normal=21.5MPa Normal=20.4 MPa y 10.75 10.2 16.8 radius max shear Max normal 27 Min normal -6,6 Theta(p) -26.3 x Shear=13.4

Normal=2.3ksi Normal=6.Oksi Y Normal=9.7ksi Y Shear=1.04ksi Shear=0.7ksi X A B с Shear=0 X Z BI

FOR EACH SLIDE

-Determine the MAXIMUM and MINIMUM NORMAL STRESS and the MAXIMUM SHEAR STRESS for each slide.

-Determine the PRINCIPAL PLANES and the SHEAR PLANES.

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Answer #1

O Given that Oy 20.4 mpa Principal stresses ☺ ny = 13.4 mpa Iman = A ontoy 2 1 Ray Eus Oman = 9+504) 4 22 h Oman = (2004) + (=) manimom shear stress kman = Oman- smin 27.out 6.64 2 Eman = 16.84 mpa - osientation of manimom shear plau a tan (20) = -oxorientation of Sman- Since Bay olevenses tan (20p) = 2 Eny Jy-on (2) (-19.9) its directio Eaulop.) -21.5 ope-30-81) e) OrientEman = Sman-omin 2.7to. 1.55ksi reman = 1.55 ksi gou () Lay = 0.7 ksi B Zay Jy z orgi =) Oman - (8)+se) +(6.0) M 6.08 ksi Om

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