Question

G Listed below are the amounts of mercury in parts per millorar em found in tuna sushi sampled at different stores. The sample mean is 1.0.9 ppm and the sample standard deviation 0.210 ppm. Use technology to construct a 90% confidence interval state of the man amount of mercury in the population 0.87 0.77 1.21 What is the confidence interval calimate of the mean amount of mercury in the population? pomene som (Round to three decimal places as needed)

Answer 1

The sample mean ()=1.099

T

Sample SD(s)=0.210

Sample size(n)=7

The 90% confidence interval for the population mean ($\mu$) is given by

$(\bar{x}\pm\frac{s}{\sqrt{n}}*t_{0.05,n-1})$

0.210 i.e.(1.099 * 10.05,6) V7

$i.e.\; (1.099\pm\frac{0.210}{\sqrt{7}}*1.943)$

$i.e.\; (1.099\pm0.1542208439)$

$\therefore\; 0.945<\mu<1.253$

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