Question

Question 5 In the beam below, calculate the bending moment at point A. Take L-13 and remember that both the loads and the di ,4LhN 4 kN/m me x X D B 1 43 * 1 → - Li L. expressed in terms of L.

Answer 1

In this question we have to find the moment at A point

is UVL maxat center In this problem loading und zero at both ends ut R, and Rz be the reaction at support We know from triangulas loading the total lood = area of loading will act at controid of area 4L= 4813=52KN 52 kN/m Take ² Mizo R2X26 - 52x13 +338x17.3334 A 13m 13 m qaz + 338x 8.6667 R2 = 364 KN 5QKN. 338KN 3381N 2 Fy-0 I Rat R2 = 2x338452 R₂ wlol → K 28 . R2 13 13 Ry = 364 KN We hove to determine bending moment at point A bon which drawing free body diagram of left portion of beam from A looding at A = WA = LAX 4 = 1 / 8x4 37.5556kN WA WA = WA=445 17.3334 KN Total load at centroid = {XWA.X 1/2 = 1 2 x 4 3 2 1 1 2 3 122.897} A = 32.5556 KN 18 at برای 534-2.8889 m from or 1.404sm from a moment at AS MA = 364x18 23 37.5556X1.44415 3 MA = 1523.086 KN-m N-m