Question

Problem 2: A beam is loaded and supported as shown below. Please draw the complete shear and bending moment diagrams 3 kN 4 kN/m 6kN С 3 kNm DI A В. -1.5 m-*-1 m 6 kN m -2 m -1.5 m 11 KN OKN 18 kN 12

Answer 1

The solution is given in following image:

3 KN 4 kN/m blw 0 cutting out AB at X-0 0 at 2915 -6 KN D 4 kN/m B x = (-42) KN 6 KN-M 3kNam ↑ 3km ma Im x² 18 kW 3 kN-m ب۷ 2 (-4x² -3) KNom 2 at no = -3KN-m. 1.5m Im 2m 15 at x1.5 -7.5 knom (2 B G C Cutting between VEL 3 4 KNlm 3kw-m. K 1.5m kay Vx 4.5 18 KN at Keby 12 ken. May WENZ 3 -3.5 V x = [18 - 4(1.5+x)] kn Hat xxl gen [ 4(1-5+2)> [5+X) + 12x - 3] ww- 7.5 Mx 2 Latuco -7.5KN-ni. atas +2.5 kNm Vxl Shear force) 2. Mal Bending momorit) 3 Cutting allt between cgo 4 kN/m I gm 3kw-m diagram based on equations Mx Ve CGKN-m 1.5 KL=0 18 8 kn. Nx= 18 - 4(2.5+x)] W 12:2 OKN Cutting between DE from Ma sight! (4(2-5+2) *Peak 3] +181.* 1 + 2) 3 Me V x = -3 KN lathan at el •3.5kN-m 0 X : 32 Maa at x=3 4.5 kw.m Vx 3 KN at a = 1.5 4.15 KW am

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