Please show all steps clearly, thanks! Generator 13800V 12MVA Wye grounded Xd" = 0.17, Xd'=0:30, and Xd = 1 pu, and Td"=.05, Td'=1 TA=0.1 13800-20kV 12MVA A A Z=j 0.06pu Use a base of 13.8 kV, 12 MVA in generator circuit A three-phase short-circuit occurs on the line side of the circuit breaker when the generator is operated at rated terminal voltage and at no-load. The breaker interrupts the fault 3 cycles after fault inception. Determine (a) the subtransient current...
1. A three-phase synchronous generator connected to a 345-KV transmission line through a transformer as shown in Figure P1. Parameters of both generator and transformer are given in the figure. Transformer losses and exciting current are neglected. A three-phase short-circuit occurs on the line side of the circuit breaker when the generator is operated at rated terminal voltage and at no-load. The breaker interrupts the fault three cycles after fault inception. Neglect the effect of the transformer on the time...
Four-bus power system shown in Fig. 1 are as follows: Generator G1: 200 MVA, 7.2 kv, X -0.15 p.u Generator G2: 250 MVA, 9.6 kV, X-0.12 p.u Generator G3: 500 MVA, 10 kV, X-0.25 p.u Transformer T1:200 MVA, 7.2 Δ /132 Y kV, X= 0.05 p.u Transformer T2: 250 MVA, 9.6 Δ /132 Y kV, X =0.15 p.u Transformer T3: 500 MVA, 10 Δ /132 Y kV, x-0.1 p.u Each 132-kV line:X,-10 Ω 1- A three-phase short circuit occurs at...
Transformer TI : 50 MVA, 10 kV Y/138 kV Y, X=0.10 per unit; Transformer T2: 100 MVA, 15 kV D/138 kV Y, X-0.10 per unit; Each 138-kV line: X1-400 A three-phase short circuit occurs at bus 5, where the prefault voltage is 15 kV. Prefault load current is neglected. (a)Draw the positive-sequence reactance diagram in per-unit on a 100-MVA, 15-kV base in the zone of generator G2. Determine: (b) the The'venin equivalent at the fault, (c) the subtransient fault current...
Problem 2 (50 points): The synchronous generator shown in the figure below is operated at its rated apparent power (100 MVA), 0.95 pf. lagging, and 5% above rated voltage. Determine the subtransient fault current if a three phase short circuit fault occurs at the terminal of the motor (Bus 2) T1 2 100 MVA 100 MVA 13.8 kV 13.8 kV Δ/138 kVY X" = 0.15 X = 0.10 100 MVA 138 kV Y/13.8 kV Δ X0.10 100 MVA 13.8 kV...
4. The following system delivers 40MW at 0.8 pf lagging to the grid at 110kV. In the middle of the line there is a zero resistance three-phase short circuit. What is the voltage at the fault location prior to the fault? Using this pre-fault voltage, calculate the three phase sub-transient short circuit current. P = 40 MW cos = 0,8ind 1 = 50 km x=0,2 12/km -0 + UN - 10,5 kV 110/10,5 kV SN 250 MVA SN 250 MVA...
please solve E and F only 2. (40 points) As shown in Figure 1, a synchronous generator and motor are rated 100 MVA, 13.8 kV. X 0.2 per unit, X 0.15 p t, and X 0.305 per unit. The synchronous generator is operating at 100 MVA, 0.95 p.f lagging and at 1.05 per unit voltage when a three-phase short circuit occurs at bus 2 Please use the direct method to calculate the per-unit values of (a) subtransient generator current (g)....
2. A three-phase short circuit occurs at the bus 1 for the system shown in figure below. Neglecting prefault currents and assuming that the generator is operating at its rated voltage, determine the subtransient fault current using superposition. bus 1 bus 2 j6522 ww m AY 25 MVA 13.8 kV 15% 25 MVA 13.2/69 KV 11% 25 MVA 69/13.2 kV 11% 15 MVA 13 kV 15%
2. A single-line diagram of the power system considered is shown in Figure P2a, where negative- and zero-sequence reactances are also given. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn = 0.05 per unit on the motor base. The per-unit zero-, positive and negative-sequence networks on a 100-MVA is shown in Figure P26, 13.8-kV base in the zone of the generator. a. Reduce the sequence networks to their...
Question3 3000 kVA / 0.09 p.u. Alternators 2 40004VA 0.12 p.u 6kV Busbars 4000 LVA 0.05 p.. Transmission Lines Lines 4000 kV 0.05 p.ย. Step-Up Transformers 5000 kVA 5000 kVA 0.06 р.u. 0.06 p.u. 11 kV Basbars -150 kVA 0.05 pu. Secondary feeder line Step-Down 1500 kVA 0.03 p.u 415 V Busbars Fault Point Figure Q3 Figure Q3 shows a power system comprising two three phase alternators supplying 6 kV busbars. I wo paralilel transmission lines fed from these busbars...