My degree of freedom is 0.18 but I don't know the p value nor the conclusion. I have the chi square distribution for the p value below but I'm very confused on what any of this means
Homework Answers
Degree of freedom can't be less than 1 . It should be always 1 or more than 1
Look at the table what u have provided in that minimum degrees of freedom is always 1 or more than 1
For example: In chi square test if you have 5 values than 5-1(N-1) = 4 is the degrees of freedom.
If more than two either coloums are rows are present then (r-1)(c-1) is the degrees of freedom.
So please check the degrees of freedom can't be less than 1
Add Answer to:
My degree of freedom is 0.18 but I don't know the p value nor
the conclusion....
please answer clearly so i can understand, thank you. 2. 10-points: The MN blood group in...
please answer clearly so i can understand, thank you.
2. 10-points: The MN blood group in humans is under the control of a pair of co-dominant alleles LM and LN. I a group of 556 Individuals, the following genotypic frequencies are found: 167 MM 280 MN 109 NN a) Calculate the frequency of the LM and LN alleles Note: the degrees of freedom is interestingly "1" since while there are genotypes.these are determined by only 2 allelic frequencies. Our book...
Help with this chi square. A-E! 13) You perform a chi square test on a monohybrid...
Help with this chi square. A-E!
13) You perform a chi square test on a monohybrid cross (Aa x Aa) and determine that chi square = 3.22. (HINT: Your df is the number of phenotypic groups minus 1). What is your p value based on this table? A. 3.22- B. 0.2 Probability (p) D. Between 0.5 and 0.2 0.90 | D..0 0.05 | 0.01 | 0.001 2 10.02 0.46 1.64 3.846.64 10.83 1.393.22 5.99 9.21 13.82 3 0.58 2.37 4.64...
The type of household for the U.S. population and for a random sample of 411 households...
The type of household for the U.S. population and for a random sample of 411 households from the community Dove Creek, Montana, are shown (based on Statistical Abstract of the United States) Observed Number of Percent of U.S. Households in Type of Househol Households Dove Creek 102 26% Married with children 112 29% Married, no children Single parent 9% One person 25% 96 11% Other (e.g., roommates, siblings) 68 Use a 5% level of significance to test the claim that...
A corn genetics lab. i got total chi-square of 14.34. And the number of degrees of...
A
corn genetics lab.
i got total chi-square of 14.34. And the number of degrees of
freedom of 1.
How can I find the probability of a Match base on the table?
please explain.
Degree of Freedom 0.99 0.000 0.020 0.115 0.297 0.554 0.872 1.239 1.647 2.088 2.558 3.053 3.571 4.107 4.660 5.229 5.812 6.408 7.015 7.633 8.260 9.542 10.856 12.198 13.565 14.953 22.164 Probability of Exceeding the Critical Value 0.95 0.90 0.75 0.50 0.25 0 .10 0.0040.016 0.1020.455 1.32...
For the below output, what was the test used, the p-value and the conclusion? a. An...
For the below output, what was the test used, the p-value and
the conclusion?
a.
An F test, with 1 and 94 degrees of freedom; p
= 0.000;reject the null
b.
A chi-square test with 4 degrees of freedom; p = 0.383; do not
reject the null.
c.
A t-test with 91 degrees of freedom; p =
0.000; reject the null
d.
An F test with 4 and 91 degrees of freedom; p
= 0.000; reject the null
lSummary of...
test. Use the Chi-square table provided by the TA. In the lab write-up answer these questions:...
test. Use the Chi-square table provided by the TA. In the lab write-up answer these questions: 1. What does it mean if a locus is in Hardy- Weinberg proportions?, it 2. Can one locus be in Hardy-Weinberg proportions and the other not? 3. Why or why not? C. The Next Generation and Genetic Drift: Before you begin, do you expect allele frequencies to change from one generation to the next if the om? What about Degrees of Freedom 0.01 1.610...
Determine (a) the test statistic, (b) the degrees of freedom, (c) the P-alue, and (d) test...
Determine (a) the test statistic, (b) the degrees of freedom, (c) the P-alue, and (d) test the hypothesis at the a-0.05 level of significance. Outcome Obsenved Expected 25 25 25 25 A B C Do 22 28 24 26 H,: At least one of the proportions is different from the others Click the icon to wew the chi-square distribution table Round to two decimal places as needed.) (b) (True False) The number of degrees of freedom is oneless than the...
For the below output, what was the test used, the p-value and the conclusion? a. An F test...
For the below output, what was the test used, the p-value and
the conclusion?
a.
An F test, with 1 and 94 degrees of freedom; p
= 0.000;reject the null
b.
A chi-square test with 4 degrees of freedom; p = 0.383; do not
reject the null.
c.
A t-test with 91 degrees of freedom; p =
0.000; reject the null
d.
An F test with 4 and 91 degrees of freedom; p
= 0.000; reject the null
lSummary of...
Conduct the hypothesis test and provide the test statistic, critical value and P-value, and state the conclusion A package of 100 candies are distributed with the following color percentages 13% r...
Conduct the hypothesis test and provide the test statistic, critical value and P-value, and state the conclusion A package of 100 candies are distributed with the following color percentages 13% red 20% ora ge, 15% yellow 12% br dlaimed. Use a 0.10 significance level. EEB Click the icon to view the color counts for the candy in the package Click here fo view the chi-square distribution table, 25% blue and 15% g een Use the given sa ple data to...
Practice questions for BIO 340 (Exam 2) I need help with these questions Please. WILL GIVE...
Practice questions for BIO 340 (Exam 2) I need help with these
questions Please. WILL GIVE GOOD RATING
1. Wild type blue-eyed mary has blue flowers. Two genes control the pathway that makes the blue pigment: The product of gene W turns a white precursor into magenta pigment. The product of gene M turns the magenta pigment into blue pigment. Each gene has a recessive loss-of-function allele: w and m, respectively. A double heterozygote (Ww Mm) is self-pollinated. What proportion...
please answer clearly so i can understand, thank you.
2. 10-points: The MN blood group in humans is under the control of a pair of co-dominant alleles LM and LN. I a group of 556 Individuals, the following genotypic frequencies are found: 167 MM 280 MN 109 NN a) Calculate the frequency of the LM and LN alleles Note: the degrees of freedom is interestingly "1" since while there are genotypes.these are determined by only 2 allelic frequencies. Our book...
Help with this chi square. A-E!
13) You perform a chi square test on a monohybrid cross (Aa x Aa) and determine that chi square = 3.22. (HINT: Your df is the number of phenotypic groups minus 1). What is your p value based on this table? A. 3.22- B. 0.2 Probability (p) D. Between 0.5 and 0.2 0.90 | D..0 0.05 | 0.01 | 0.001 2 10.02 0.46 1.64 3.846.64 10.83 1.393.22 5.99 9.21 13.82 3 0.58 2.37 4.64...
The type of household for the U.S. population and for a random sample of 411 households from the community Dove Creek, Montana, are shown (based on Statistical Abstract of the United States) Observed Number of Percent of U.S. Households in Type of Househol Households Dove Creek 102 26% Married with children 112 29% Married, no children Single parent 9% One person 25% 96 11% Other (e.g., roommates, siblings) 68 Use a 5% level of significance to test the claim that...
A
corn genetics lab.
i got total chi-square of 14.34. And the number of degrees of
freedom of 1.
How can I find the probability of a Match base on the table?
please explain.
Degree of Freedom 0.99 0.000 0.020 0.115 0.297 0.554 0.872 1.239 1.647 2.088 2.558 3.053 3.571 4.107 4.660 5.229 5.812 6.408 7.015 7.633 8.260 9.542 10.856 12.198 13.565 14.953 22.164 Probability of Exceeding the Critical Value 0.95 0.90 0.75 0.50 0.25 0 .10 0.0040.016 0.1020.455 1.32...
For the below output, what was the test used, the p-value and
the conclusion?
a.
An F test, with 1 and 94 degrees of freedom; p
= 0.000;reject the null
b.
A chi-square test with 4 degrees of freedom; p = 0.383; do not
reject the null.
c.
A t-test with 91 degrees of freedom; p =
0.000; reject the null
d.
An F test with 4 and 91 degrees of freedom; p
= 0.000; reject the null
lSummary of...
test. Use the Chi-square table provided by the TA. In the lab write-up answer these questions: 1. What does it mean if a locus is in Hardy- Weinberg proportions?, it 2. Can one locus be in Hardy-Weinberg proportions and the other not? 3. Why or why not? C. The Next Generation and Genetic Drift: Before you begin, do you expect allele frequencies to change from one generation to the next if the om? What about Degrees of Freedom 0.01 1.610...
Determine (a) the test statistic, (b) the degrees of freedom, (c) the P-alue, and (d) test the hypothesis at the a-0.05 level of significance. Outcome Obsenved Expected 25 25 25 25 A B C Do 22 28 24 26 H,: At least one of the proportions is different from the others Click the icon to wew the chi-square distribution table Round to two decimal places as needed.) (b) (True False) The number of degrees of freedom is oneless than the...
For the below output, what was the test used, the p-value and
the conclusion?
a.
An F test, with 1 and 94 degrees of freedom; p
= 0.000;reject the null
b.
A chi-square test with 4 degrees of freedom; p = 0.383; do not
reject the null.
c.
A t-test with 91 degrees of freedom; p =
0.000; reject the null
d.
An F test with 4 and 91 degrees of freedom; p
= 0.000; reject the null
lSummary of...
Conduct the hypothesis test and provide the test statistic, critical value and P-value, and state the conclusion A package of 100 candies are distributed with the following color percentages 13% red 20% ora ge, 15% yellow 12% br dlaimed. Use a 0.10 significance level. EEB Click the icon to view the color counts for the candy in the package Click here fo view the chi-square distribution table, 25% blue and 15% g een Use the given sa ple data to...
Practice questions for BIO 340 (Exam 2) I need help with these
questions Please. WILL GIVE GOOD RATING
1. Wild type blue-eyed mary has blue flowers. Two genes control the pathway that makes the blue pigment: The product of gene W turns a white precursor into magenta pigment. The product of gene M turns the magenta pigment into blue pigment. Each gene has a recessive loss-of-function allele: w and m, respectively. A double heterozygote (Ww Mm) is self-pollinated. What proportion...
Most questions answered within 3 hours.
-
Why is Kevlar a stronger fabric then dacron? Provide two reasons
involving structures.
asked 1 minute ago -
Suppose you have a checkers board. (8 squares wide and 8
squares long) and you
have...
asked 21 minutes ago -
Given the following function: QD = 200 - 5.25P
7.1 Derive the Regular Demand Function
7.2...
asked 16 minutes ago -
The following results were obtained as
part of a multiple regression analysis involving 3 independent
variables:...
asked 1 hour ago -
The time to complete a standardized exam is approximately normal
with a mean of 70 minutes...
asked 3 hours ago -
Two thousand randomly selected adults were asked whether or not
they have ever shopped on the...
asked 3 hours ago -
Estimate the diffusion coefficient for methyl phenyl sulfide in
water at 25 degrees Celcius.
asked 2 hours ago -
10.g of a certain metal absorb 40. cal of heat and the temperature
is abserved to...
asked 3 hours ago -
How many milliliters of 0.0695 M Ca( OH)
2would be required to exactly neutralize 176 mL...
asked 3 hours ago -
A telephone survey uses a random digit dialing machine to call
subjects. The random digit dialing...
asked 4 hours ago -
How can having too little or too much of a certain
protein cause problems for an...
asked 5 hours ago -
Assume a muscle has a PCSA = 20 cm2 and Lo = 12 cm. Assume it...
asked 7 hours ago