If you were to conduct a cross between two individuals with genotypes Aa:Bb:Cc:Dd x Aa:Bb:Cc:dd, how many genotypes would you expect to see in the offspring?
Ans. 81 genotypes
No. Of heterozygous positions = 4( Aa, Bb, Cc and Dd)
No. Of different genotypes = 3n
= 34
= 81 genotypes
If you were to conduct a cross between two individuals with genotypes Aa:Bb:Cc:Dd x Aa:Bb:Cc:dd, how...
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please help with these 3 questions. thank you!
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