Question

A Review Constants In the circuit of the figure (Figure 1), take E = 12.0 V, Ex = 6.00 V. Ez = 3.00 V, R1 = 1.10 12. R2 = 2.0

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Eq (③ x 7.10 + E, ③ x 1.10 42.6 – 22.0 I2 - 7. Iz = 0 16.5 = 1.21 I 2 7 7.8I3 + 26.) – 20. 8 I 2 = 0 26.1 Iza 20. & - 1.2 54

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