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A resistor with R=20.0 22 and an inductor with L = 0.600 H are connected in series to a battery that has emf 50.0 V and negli
A toroidal solenoid has 570 tums, cross-sectional area 6.90 cm², and mean radius 4.20 cm - Part A Calculate the coils self-i
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Answer #1

1)

Energy stored in the inductor is given as

E = 1/2 * L * I2

0.4 = 1/2 * 0.6 * I2

I = 1.1547 amps

voltage across Resistor = IR = 23.1 V

so,

voltage across inductor = 50 - 23.1

voltage across inductor = 26.9 Volts

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