Summary-This is the basic problem. I have provided the step by step solution.
The critical angle for a light from the bottom of a swimming pool shining upward toward...
You are at the bottom of your swimming pool, shining a flashlight upwards. What angle would you have to shine the light; relative to the surface of the water, for the light to emerge parallel to the surface (n = 1.3)? Anwer in degrees.
A flashlight on the bottom of a 3.95 m deep swimming pool sends a ray upward and at an angle so that the ray strikes the surface of the water 1.65 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water's surface?
A flashlight on the bottom of a 3.93 m deep swimming pool sends a ray upward at an angle so that the ray strikes the surface of the water 1.89 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water's surface?
Grade Cate Description Policies: Light is travel from the bottom of a swimming pool to the air above. If the angle between the surface of the water and light refraction of water is 1.3 from the bottom of the pool is 60°, what is the angle of refraction. The index of You can che You can view give up on a You can keep you get it rig You lose S% o answer in you attempt at tha degrees D...
9) A small light fixture is on the bottom of a swimming pool,0.75 m below the surface. The lightemerging from the water forms a circle on the still water surface.What is the diameter of this circle? m
You are standing at the edge fo a swimming pool and shining a laser pointer onto the water surface. The laser beam hits the water at an angle of 50.8 deg above the horizontal. Some of the lights reflects off the water surface, and some enter the water. Find the angle between the reflected and refracted rays. From Snell's law I got the refracted angle of the laser beam= 35.64 deg. Then I thought it was just the difference between...
An expensive spotlight is located at the bottom of a gold-plated swimming pool of depth d = 1.00 m (see Figure). Determine the diameter of the circle from which light emerges from the tranquil surface of the pool.
If a laser is shining directly down onto the surface of water from an angle of 0 degrees (completely parallel to the normal), what percentage of the light enters the water and what percentage would be reflected back upward?
L. A flashlight on the bottom of a 4.00 m deep swimming pool sends a ra d at an angle so that the ray strikes the surface of the water 2.00 m fromt directly above the flashlight. What angle (in air) does the emerging ray make water's surface? (10) he point
In the figure, a 2.0-m-long vertical pole extends from the bottom of a swimming pool to a point 50.0 cm above the water. Sunlight is incident at angle θ = 50.0°. What is the length in meters of the shadow of the pole on the level bottom of the pool? The water has an index of refraction of 1.33.