You are at the bottom of your swimming pool, shining a flashlight upwards.
What angle would you have to shine the light; relative to the surface of the water, for the light to emerge parallel to the surface (n = 1.3)? Anwer in degrees.
You are at the bottom of your swimming pool, shining a flashlight upwards. What angle would...
The critical angle for a light from the bottom of a swimming pool shining upward toward the pool's surface is the angle
A flashlight on the bottom of a 3.95 m deep swimming pool sends a ray upward and at an angle so that the ray strikes the surface of the water 1.65 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water's surface?
A flashlight on the bottom of a 3.93 m deep swimming pool sends a ray upward at an angle so that the ray strikes the surface of the water 1.89 m from the point directly above the flashlight. What angle (in air) does the emerging ray make with the water's surface?
L. A flashlight on the bottom of a 4.00 m deep swimming pool sends a ra d at an angle so that the ray strikes the surface of the water 2.00 m fromt directly above the flashlight. What angle (in air) does the emerging ray make water's surface? (10) he point
A flashlight is held at the edge of a swimming pool at a height h = 2.2 m such that its beam makes an angle of θ = 58 degrees with respect to the water's surface. The pool is d = 1.5 m deep and the index of refraction for air and water are n1=1 and n2 = 1.33, respectively. What is the horizontal distance D, from the edge of the pool to the port on the bottom of the pool...
A flashlight is held at the edge of a swimming pool at a height h = 2.4 m such that its beam makes an angle of θ = 41 degrees with respect to the water's surface. The pool is d = 2.25 m deep and the index of refraction for air and water are n1 = 1 and n2 = 1.33, respectively.what is the horizontal distance, D, from the edge of the pool to the point on the bottom of...
Grade Cate Description Policies: Light is travel from the bottom of a swimming pool to the air above. If the angle between the surface of the water and light refraction of water is 1.3 from the bottom of the pool is 60°, what is the angle of refraction. The index of You can che You can view give up on a You can keep you get it rig You lose S% o answer in you attempt at tha degrees D...
(20%) Problem 2: A flashlight is held at the edge of a swimming pool at a height h = 2.4 m such that its beam makes an angle of θ 41 degrees with respect to the water's surface. The pool is d = 2.25 m deep and the index of refraction for air and water are n1 = 1 and n2-1.33, respectively Randomized Variables h 2.4 m d 2.25 m 6% 41 degrees What is the horizontal distance, D, from...
You are standing at the edge fo a swimming pool and shining a laser pointer onto the water surface. The laser beam hits the water at an angle of 50.8 deg above the horizontal. Some of the lights reflects off the water surface, and some enter the water. Find the angle between the reflected and refracted rays. From Snell's law I got the refracted angle of the laser beam= 35.64 deg. Then I thought it was just the difference between...
You are standing in a 1.5-m-deep swimming pool at night. The water is very still. You hold a laser pointer just above the water's surface and shine it nearly parallel to the surface, but tilted slightly down so that the beam enters the water 3.5mfrom you. How far from you does the beam strike the bottom of the pool? Index of refraction of the water is 1.33.