Question

A bird going 28.8 km/hr is pursuing a bee. The bee is flying in the same direction as the bird at 10.8 km/hr. When the bird is but 3.00 meters behind the bee a wind begins which blows backwards so that the bird’s acceleration is ­5.00 m/s/s and the bee’s acceleration is ­2.00 m/s/s. They both continue to fly forward and bird misses the bee when it first catches up. They both continue to fly forward in the wind. How fast is the bird going the second time it catches up with the bee?

Answer 1

05182 & A2=2 m/82 +3 Bee 1/2=10.8 km by be in br te 4SHJ524X15X3 Idiglanu Govered diolanu Bird covered by Bird int time A time Vi=28.8 km hr it= time in which biod 3mm First 2x1.5 caught be for the 10.4–1542) = ( 31-4125443 7-23-dvere anys V2 = 10 dys - 3m la 12 2.5+ ²+ + ² = 3 51-1-5+²=3 11.5t² 5 4+3=0 Hohet 2-548, 44=0.784 the be first time at di= 0.7848es but ut Migged and caught at second timo ngoing Let velocity of bird second time V=U-at V= 181-15x0.784) go bird caraght V=4.02 m/sANS CScanned with CamScanner