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Explain why the matrix is not diagonalizable. 600] A = 1 60 0 0 6 O...
linear algebra Explain why the matrix is not diagonalizable. A= 8 0 0 1 8 0...
linear algebra
Explain why the matrix is not diagonalizable. A= 8 0 0 1 8 0 0 0 8 O A is not diagonalizable because it only has one distinct eigenvalue. O A is not diagonalizable because it only has two distinct eigenvalues. O A is not diagonalizable because it only has one linearly independent eigenvector. O A is not diagonalizable because it only has two linearly independent eigenvectors.
DETAILS LARLINALG8 7.R.019. Explain why the matrix is not diagonalizable. 200 A= 1 2 0 0...
DETAILS LARLINALG8 7.R.019. Explain why the matrix is not diagonalizable. 200 A= 1 2 0 0 0 2 A is not diagonalizable because it only has one distinct eigenvalue. A is not diagonalizable because it only has two distinct eigenvalues. A is not diagonalizable because it only has one linearly independent eigenvector. A is not diagonalizable because it only has two linearly independent eigenvectors.
DETAILS LARLINALG8 7.2.050. Show that the matrix is not diagonalizable. [ ] : 0 The matrix...
DETAILS LARLINALG8 7.2.050. Show that the matrix is not diagonalizable. [ ] : 0 The matrix is not diagonalizable because it only has one linearly independent eigenvector. The matrix is not diagonalizable because it only has one distinct eigenvalue. The matrix is not diagonalizable because [*] is not an eigenvector. The matrix is not diagonalizable because k is not an eigenvalue.
Let A be the matrix To 1 0] A= -4 4 0 1-2 0 1 (a)...
Let A be the matrix To 1 0] A= -4 4 0 1-2 0 1 (a) Find the eigenvalues and eigenvectors of A. (b) Find the algebraic multiplicity an, and the geometric multiplicity, g, of each eigenvalue. (c) For one of the eigenvalues you should have gi < az. (If not, redo the preceding parts!) Find a generalized eigenvector for this eigenvalue. (d) Verify that the eigenvectors and generalized eigenvectors are all linearly independent. (e) Find a fundamental set of...
Show that the matrix is not diagonalizable. 2 43 0 21 0 03 STEP 1: Use...
Show that the matrix is not diagonalizable. 2 43 0 21 0 03 STEP 1: Use the fact that the matrix is triangular to write down the eigenvalues. (Enter your answers from smallest to largest.) -- STEP 2: Find the eigenvectors x, and X corresponding to d, and 12, respectively, STEP 3: Since the matrix does not have Select linearly independent eigenvectors, you can conclude that the matrix is not diagonalizable.
4. (15 pts Consider the following direction fields IV VI (5 pts)Which of the direction fields corresponds to the system x -Ax, where A is a 2x2 matrix with eigenvalues λ,--1 and λ2-2 and correspondin...
4. (15 pts Consider the following direction fields IV VI (5 pts)Which of the direction fields corresponds to the system x -Ax, where A is a 2x2 matrix with eigenvalues λ,--1 and λ2-2 and corresponding eigenvectors vand v- 1? a. is a 2x2 matrix with repeated eigenvalue λ = 0 with defect 1 (has only one linearly independent eigenvector, not two.) and corresponding eigenvector vi- 13 (5 pts) Which of the direction fields corresponds to the system x -Cx, where...
Show that the matrix is not diagonalizable. 1-42 13 0 02 STEP 1: Use the fact...
Show that the matrix is not diagonalizable. 1-42 13 0 02 STEP 1: Use the fact that the matrix is triangular to write down the eigenvalues. (Enter your answers from smallest to largest.) (11.22) = STEP 2: Find the eigenvectors Xi and X2 corresponding to 1, and 12, respectively. X1 = X2 - STEP 3: Since the matrix does not have ---Select-- linearly independent eigenvectors, you can conclude that the matrix is not diagonalizable.
2. (5' each) Give short answers: (a) True or false: If Ai-Adi for some real number λ, then u is a...
linear algebra question
2. (5' each) Give short answers: (a) True or false: If Ai-Adi for some real number λ, then u is an eigenvector of matrix A. If a square matrix is diagonalizable, then it has n distinct real eigenvalues. Two vectors of the same dimension are linearly independent if and only if one is not a multiple of the other. If the span of a set of vectors is R", then that set is a basis of R...
Assume all matricies are Mmxm(R) unless otherwise specified. 1. (1 point) Prove or disprove that the...
Assume all matricies are Mmxm(R) unless otherwise specified. 1. (1 point) Prove or disprove that the eigenvalues of A and AT are the same. 2. (2 points) Let A be a matrix with m distinct, non-zero, eigenvalues. Prove that the eigenvectors of A are linearly independent and span R”. Note that this means in this case) that the eigenvectors are distinct and form a base of the space. 3. (1 point) Given that is an eigenvalue of A associated with...
Please do number 2 Assume all matricies are Mmxm(R) unless otherwise specified. 1. (1 point) Prove...
Please do number 2
Assume all matricies are Mmxm(R) unless otherwise specified. 1. (1 point) Prove or disprove that the eigenvalues of A and AT are the same. 2. (2 points) Let A be a matrix with m distinct, non-zero, eigenvalues. Prove that the eigenvectors of A are linearly independent and span R”. Note that this means in this case) that the eigenvectors are distinct and form a base of the space. 3. (1 point) Given that is an eigenvalue...
linear algebra
Explain why the matrix is not diagonalizable. A= 8 0 0 1 8 0 0 0 8 O A is not diagonalizable because it only has one distinct eigenvalue. O A is not diagonalizable because it only has two distinct eigenvalues. O A is not diagonalizable because it only has one linearly independent eigenvector. O A is not diagonalizable because it only has two linearly independent eigenvectors.
DETAILS LARLINALG8 7.R.019. Explain why the matrix is not diagonalizable. 200 A= 1 2 0 0 0 2 A is not diagonalizable because it only has one distinct eigenvalue. A is not diagonalizable because it only has two distinct eigenvalues. A is not diagonalizable because it only has one linearly independent eigenvector. A is not diagonalizable because it only has two linearly independent eigenvectors.
DETAILS LARLINALG8 7.2.050. Show that the matrix is not diagonalizable. [ ] : 0 The matrix is not diagonalizable because it only has one linearly independent eigenvector. The matrix is not diagonalizable because it only has one distinct eigenvalue. The matrix is not diagonalizable because [*] is not an eigenvector. The matrix is not diagonalizable because k is not an eigenvalue.
Let A be the matrix To 1 0] A= -4 4 0 1-2 0 1 (a) Find the eigenvalues and eigenvectors of A. (b) Find the algebraic multiplicity an, and the geometric multiplicity, g, of each eigenvalue. (c) For one of the eigenvalues you should have gi < az. (If not, redo the preceding parts!) Find a generalized eigenvector for this eigenvalue. (d) Verify that the eigenvectors and generalized eigenvectors are all linearly independent. (e) Find a fundamental set of...
Show that the matrix is not diagonalizable. 2 43 0 21 0 03 STEP 1: Use the fact that the matrix is triangular to write down the eigenvalues. (Enter your answers from smallest to largest.) -- STEP 2: Find the eigenvectors x, and X corresponding to d, and 12, respectively, STEP 3: Since the matrix does not have Select linearly independent eigenvectors, you can conclude that the matrix is not diagonalizable.
4. (15 pts Consider the following direction fields IV VI (5 pts)Which of the direction fields corresponds to the system x -Ax, where A is a 2x2 matrix with eigenvalues λ,--1 and λ2-2 and corresponding eigenvectors vand v- 1? a. is a 2x2 matrix with repeated eigenvalue λ = 0 with defect 1 (has only one linearly independent eigenvector, not two.) and corresponding eigenvector vi- 13 (5 pts) Which of the direction fields corresponds to the system x -Cx, where...
Show that the matrix is not diagonalizable. 1-42 13 0 02 STEP 1: Use the fact that the matrix is triangular to write down the eigenvalues. (Enter your answers from smallest to largest.) (11.22) = STEP 2: Find the eigenvectors Xi and X2 corresponding to 1, and 12, respectively. X1 = X2 - STEP 3: Since the matrix does not have ---Select-- linearly independent eigenvectors, you can conclude that the matrix is not diagonalizable.
linear algebra question
2. (5' each) Give short answers: (a) True or false: If Ai-Adi for some real number λ, then u is an eigenvector of matrix A. If a square matrix is diagonalizable, then it has n distinct real eigenvalues. Two vectors of the same dimension are linearly independent if and only if one is not a multiple of the other. If the span of a set of vectors is R", then that set is a basis of R...
Assume all matricies are Mmxm(R) unless otherwise specified. 1. (1 point) Prove or disprove that the eigenvalues of A and AT are the same. 2. (2 points) Let A be a matrix with m distinct, non-zero, eigenvalues. Prove that the eigenvectors of A are linearly independent and span R”. Note that this means in this case) that the eigenvectors are distinct and form a base of the space. 3. (1 point) Given that is an eigenvalue of A associated with...
Please do number 2
Assume all matricies are Mmxm(R) unless otherwise specified. 1. (1 point) Prove or disprove that the eigenvalues of A and AT are the same. 2. (2 points) Let A be a matrix with m distinct, non-zero, eigenvalues. Prove that the eigenvectors of A are linearly independent and span R”. Note that this means in this case) that the eigenvectors are distinct and form a base of the space. 3. (1 point) Given that is an eigenvalue...
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