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DETAILS LARLINALG8 7.2.050. Show that the matrix is not diagonalizable. [ ] : 0 The matrix...
DETAILS LARLINALG8 7.R.019. Explain why the matrix is not diagonalizable. 200 A= 1 2 0 0...
DETAILS LARLINALG8 7.R.019. Explain why the matrix is not diagonalizable. 200 A= 1 2 0 0 0 2 A is not diagonalizable because it only has one distinct eigenvalue. A is not diagonalizable because it only has two distinct eigenvalues. A is not diagonalizable because it only has one linearly independent eigenvector. A is not diagonalizable because it only has two linearly independent eigenvectors.
Explain why the matrix is not diagonalizable. 600] A = 1 60 0 0 6 O...
Explain why the matrix is not diagonalizable. 600] A = 1 60 0 0 6 O A is not diagonalizable because it only has one distinct eigenvalue. O A is not diagonalizable because it only has two distinct eigenvalues. O A is not diagonalizable because it only has one linearly independent eigenvector. A is not diagonalizable because it only has two linearly independent eigenvectors
linear algebra Explain why the matrix is not diagonalizable. A= 8 0 0 1 8 0...
linear algebra
Explain why the matrix is not diagonalizable. A= 8 0 0 1 8 0 0 0 8 O A is not diagonalizable because it only has one distinct eigenvalue. O A is not diagonalizable because it only has two distinct eigenvalues. O A is not diagonalizable because it only has one linearly independent eigenvector. O A is not diagonalizable because it only has two linearly independent eigenvectors.
ASK YOUR TEACHER DETAILS LARLINALG8 7.2.023. Find the eigenvalues of the matrix and determine whether there...
ASK YOUR TEACHER DETAILS LARLINALG8 7.2.023. Find the eigenvalues of the matrix and determine whether there is a sufficient number to guarantee that the matrix is diagonalizable. (Recall that the matrix may be diagonalizable even though it is not guaranteed to be diagonalizable by the theorem shown below.) Sufficient Condition for Diagonalization If an n x n matrix A has a distinct eigenvalues, then the corresponding eigenvectors are linearly independent and A is diagonalizable. Find the eigenvalues. (Enter your answers...
DETAILS LARLINALG8 7.3.033. Show that any two eigenvectors of the symmetric matrix A corresponding to distinct...
DETAILS LARLINALG8 7.3.033. Show that any two eigenvectors of the symmetric matrix A corresponding to distinct eigenvalues are orthogonal. 3 A = Find the characteristic polynomial of A. |u-A=1 Find the eigenvalues of A. (Enter your answers from smallest to largest.) (14, 12) = Find the general form for every eigenvector corresponding to 1. (Use s as your parameter.) X1 = Find the general form for every eigenvector corresponding to 12. (Use t as your parameter.) X2 = Find x,...
CengageBrain - My Home MA 313, section 202. OL, Summer 2 2020 [0.27/0.83 Points] DETAILS PREVIOUS...
CengageBrain - My Home MA 313, section 202. OL, Summer 2 2020 [0.27/0.83 Points] DETAILS PREVIOUS ANSWERS LARLINALG8 7.3.003. Prove that the symmetric matrix is diagonalizable. (Assume that a is real.) 00 a A= 0 a 0 а 0 0 Find the eigenvalues of A. (Enter your answers as a comma-separated list. Do not list the same eigenvalue multiple times.) X = 1,0,- 1 X Find an invertible matrix P such that p-1AP is diagonal. 0 -1 Ps 1 0...
2. (5' each) Give short answers: (a) True or false: If Ai-Adi for some real number λ, then u is a...
linear algebra question
2. (5' each) Give short answers: (a) True or false: If Ai-Adi for some real number λ, then u is an eigenvector of matrix A. If a square matrix is diagonalizable, then it has n distinct real eigenvalues. Two vectors of the same dimension are linearly independent if and only if one is not a multiple of the other. If the span of a set of vectors is R", then that set is a basis of R...
Show that the matrix is not diagonalizable. 2 43 0 21 0 03 STEP 1: Use...
Show that the matrix is not diagonalizable. 2 43 0 21 0 03 STEP 1: Use the fact that the matrix is triangular to write down the eigenvalues. (Enter your answers from smallest to largest.) -- STEP 2: Find the eigenvectors x, and X corresponding to d, and 12, respectively, STEP 3: Since the matrix does not have Select linearly independent eigenvectors, you can conclude that the matrix is not diagonalizable.
Show that the matrix is not diagonalizable. 1-42 13 0 02 STEP 1: Use the fact...
Show that the matrix is not diagonalizable. 1-42 13 0 02 STEP 1: Use the fact that the matrix is triangular to write down the eigenvalues. (Enter your answers from smallest to largest.) (11.22) = STEP 2: Find the eigenvectors Xi and X2 corresponding to 1, and 12, respectively. X1 = X2 - STEP 3: Since the matrix does not have ---Select-- linearly independent eigenvectors, you can conclude that the matrix is not diagonalizable.
D.30. For the matrix a. Find the eigenvalue(s) and the eigenvector(s). b. Is matrix A diagonalizable?...
D.30. For the matrix a. Find the eigenvalue(s) and the eigenvector(s). b. Is matrix A diagonalizable? If so, what is the matrix P that diagonalizes A? c. If matrix A is diagonalizable, find the diagonal matrix D that is associated with A by using D-P AP d. If matrix A is diagonalizable, find the diagonal matrix D that is associated with A directly from the eigenvalues found in part a.
DETAILS LARLINALG8 7.R.019. Explain why the matrix is not diagonalizable. 200 A= 1 2 0 0 0 2 A is not diagonalizable because it only has one distinct eigenvalue. A is not diagonalizable because it only has two distinct eigenvalues. A is not diagonalizable because it only has one linearly independent eigenvector. A is not diagonalizable because it only has two linearly independent eigenvectors.
Explain why the matrix is not diagonalizable. 600] A = 1 60 0 0 6 O A is not diagonalizable because it only has one distinct eigenvalue. O A is not diagonalizable because it only has two distinct eigenvalues. O A is not diagonalizable because it only has one linearly independent eigenvector. A is not diagonalizable because it only has two linearly independent eigenvectors
linear algebra
Explain why the matrix is not diagonalizable. A= 8 0 0 1 8 0 0 0 8 O A is not diagonalizable because it only has one distinct eigenvalue. O A is not diagonalizable because it only has two distinct eigenvalues. O A is not diagonalizable because it only has one linearly independent eigenvector. O A is not diagonalizable because it only has two linearly independent eigenvectors.
ASK YOUR TEACHER DETAILS LARLINALG8 7.2.023. Find the eigenvalues of the matrix and determine whether there is a sufficient number to guarantee that the matrix is diagonalizable. (Recall that the matrix may be diagonalizable even though it is not guaranteed to be diagonalizable by the theorem shown below.) Sufficient Condition for Diagonalization If an n x n matrix A has a distinct eigenvalues, then the corresponding eigenvectors are linearly independent and A is diagonalizable. Find the eigenvalues. (Enter your answers...
DETAILS LARLINALG8 7.3.033. Show that any two eigenvectors of the symmetric matrix A corresponding to distinct eigenvalues are orthogonal. 3 A = Find the characteristic polynomial of A. |u-A=1 Find the eigenvalues of A. (Enter your answers from smallest to largest.) (14, 12) = Find the general form for every eigenvector corresponding to 1. (Use s as your parameter.) X1 = Find the general form for every eigenvector corresponding to 12. (Use t as your parameter.) X2 = Find x,...
CengageBrain - My Home MA 313, section 202. OL, Summer 2 2020 [0.27/0.83 Points] DETAILS PREVIOUS ANSWERS LARLINALG8 7.3.003. Prove that the symmetric matrix is diagonalizable. (Assume that a is real.) 00 a A= 0 a 0 а 0 0 Find the eigenvalues of A. (Enter your answers as a comma-separated list. Do not list the same eigenvalue multiple times.) X = 1,0,- 1 X Find an invertible matrix P such that p-1AP is diagonal. 0 -1 Ps 1 0...
linear algebra question
2. (5' each) Give short answers: (a) True or false: If Ai-Adi for some real number λ, then u is an eigenvector of matrix A. If a square matrix is diagonalizable, then it has n distinct real eigenvalues. Two vectors of the same dimension are linearly independent if and only if one is not a multiple of the other. If the span of a set of vectors is R", then that set is a basis of R...
Show that the matrix is not diagonalizable. 2 43 0 21 0 03 STEP 1: Use the fact that the matrix is triangular to write down the eigenvalues. (Enter your answers from smallest to largest.) -- STEP 2: Find the eigenvectors x, and X corresponding to d, and 12, respectively, STEP 3: Since the matrix does not have Select linearly independent eigenvectors, you can conclude that the matrix is not diagonalizable.
Show that the matrix is not diagonalizable. 1-42 13 0 02 STEP 1: Use the fact that the matrix is triangular to write down the eigenvalues. (Enter your answers from smallest to largest.) (11.22) = STEP 2: Find the eigenvectors Xi and X2 corresponding to 1, and 12, respectively. X1 = X2 - STEP 3: Since the matrix does not have ---Select-- linearly independent eigenvectors, you can conclude that the matrix is not diagonalizable.
D.30. For the matrix a. Find the eigenvalue(s) and the eigenvector(s). b. Is matrix A diagonalizable? If so, what is the matrix P that diagonalizes A? c. If matrix A is diagonalizable, find the diagonal matrix D that is associated with A by using D-P AP d. If matrix A is diagonalizable, find the diagonal matrix D that is associated with A directly from the eigenvalues found in part a.
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