At its peak, a tornado is 56.0 m in diameter and carries 400 km/h winds. What is its angular velocity in revolutions per second?
rev/s
Given the diameter of the tornado d = 56m. So its radius r = 28m. Also the velocity of the tornado v = 400km/h = 111.11m/s. The angular velocity of the tornado is given by,
Now the angular velocity in revolutions per second is,
So the angular velocity is 0.63 revolutions per second.
At its peak, a tornado is 56.0 m in diameter and carries 400 km/h winds. What...
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