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a. Calculate the dry air and water vapor mass flow rates (lb/min) if the volume flow rate is 1,000 cfm, the humidity ratio is

b. Assume the above air enters an evaporator coil at 90°F where it is cooled in a constant humidity ratio process until reach

c. Show the Part b. above cooling process on a psychrometric chart SKETCH (not the real chart, which will be used in Part B o

d. Using an energy balance, calculate the heat removed ( cooling capacity ) from the above dry air ( air only-no water vapor

e. Repeat Part d. above for the change in water vapor (Btu/min) only-you already did dry air above. Essentially, the liquid w

f. Compare your answers in Part d. and e. above and also add to get a total. Discuss and comment on a major conclusion regard

g. How many tons (200Btu/min = 1ton) is the above A/C?

h. If the COP is 4 and the cost of electricity is $0.20 per kW-hr, calculate the daily cost to condition this air for the abo

engineering   Mechanical-Engineering   
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Answer #1

Tal volume flow rate = 1000 cfus (0) = 1000 ft/usin. Humidity ratio (CO) = 0.025 Bayafx density (Sa) = 0.072 850/ft3 let, Qvpeut value of Sa in equation or Q = 1000 - Qa = 0.03 ft Tusin. Hence, mass flow rate of aff (usa) = 2 visa = Pa ba = 0.072x99water of vapour Difference in mass blow rate = my mua = 70892-0.54 Gus) =1.352 lbr/usin. .:ilb 453.592 grams :com) = 1.352 X

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