Question

Given the stress element below: 1. Draw Mohr Circle for the stress element shown below. Use proper scale and draw neatly. 2.

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Answer #1

Solution:

1)Fig 1 represents the required Mohr circle for the given state of stress,

300.0 Max shear = 2016 250.0 (-150.0, 100.0) 2000 (-150.0, 100.0) 150.0 100.0 X 50.0 Min prin = -176.6 (25.00, 0.0) 100.0 -40

Fig 1: Mohr circle for the given state of stress

2)

Please refer to fig 1 for the labelled representation of principal and max shear stress state.

3)

Please refer to table 1 to find the required values.

Results

Value Angle [deg]
Rotated Element, Normal Stress X -150.0 0.000°
Rotated Element, Normal Stress Y 200.0 90.00°
Rotated Element, Shear Stress -100.0 ---
Max Principal Stress 226.6 -75.13°
Min Principal Stress -176.6 14.87°
Max Extreme Shear Stress 201.6 -30.13°
Min Extreme Shear Stress -201.6 59.87°

Table 1 : Mohr circle result

4) Please find the following figures for initial state, principal stress state and shear state stress

Unrotated Element(Black Line in Mohrs Circle) o.y = 200.0 T= -100.0 у 1966% Ľ х O.X = -150.0 T = 100.0 T= -100.0 o.y = 200.0

Rotated Element (0.000 deg) O.y = 200.0 T= -100.0 10964 Ľ х X = -150.0 T = 100.0 T= -100.0 O.y = 200.0

Element Rotated to Max Principal Stress (-75.13 deg) 0.X = 226.6 T = 0.000 O.y = -176.6 0.000 O.y = -176.6 T+0.000 T = 0.000

Element Rotated to Max Shear Stress (-30.13 deg) O.y = 25.00 T = 201.6 0.X = 25.00 T=-2016 у X 0.X = 25.00 T = 201.6 0.y = 25

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