Rate Data Solution mL H2O2 mL KI Rate (mL O2/s) 1 5.0 10.0 3.64 x 10-2...
Rate Data
|
Solution |
mL H2O2 |
mL KI |
Rate (mL O2/s) |
|
1 |
5.0 |
10.0 |
3.64 x 10-2 |
|
2 |
10.0 |
10.0 |
7.81 x 10-2 |
|
3 |
5.0 |
20.0 |
7.14 x 10-2 |
Rate law: Since doubling either [H2O2 ] or I-] doubles the reaction rate the rate law is:
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Rate Data
Solution
mL H2O2
mL KI
Rate (mL O2/s)
1
5.0
10.0
3.64 x 10-2...
Rates of 30 Chemical Reactions II: Rate and Order of H202 Decomposition rder of Reaction H...
Rates of 30 Chemical Reactions II: Rate and Order of H202 Decomposition rder of Reaction H TEMPERATURE 20 oC 20 °c Solution 3 Solution 2 ution 1 uret ading Vol. ofO mL) (mL) Time (mL) Buretyol fO Time reading(mL) Buret reading Vol ofO (mL) Time (mL) /O 12 Slope Slope Slope Rate law: Since doubling either [H202] or [I] doubles the reaction rate the rate law is Rate Data Rate SolutionmL H20 5.0 10.0 5.0 mL KI (mL O2/s) 10.0...
Please help V THIS IS THE DATA V 2. Calculate the mol/L H2O2 reacted or A[H2O2)....
Please help
V THIS IS THE DATA V
2. Calculate the mol/L H2O2 reacted or A[H2O2). (Include units on all values and report all results to 3 significant figures.). Trial 1 Trial 2 Trial 3 Trial 4 Experiment 5 Determining Rate of Reaction: lodide Oxidation by Hydrogen peroxide Purpose: To determine the rate law and activation energy for; 21 + H202 + H+ 12 + H2O by varying reactant concentrations and reaction temperature. Results 2 3 4 40.0 40.0 40.0...
using the data above answer 6-8 the stock solution of H2O2 was 0.2M 21° + H2O2...
using the data above answer 6-8
the
stock solution of H2O2 was 0.2M
21° + H2O2 + H 2 + H2O by varying reactant concentrations and reaction temperature. Results 40.0 40.0 40.0 40.0 10.0 10.0 10.0 5.0 10.0 20.0 20.0 10.0 0.0 30.0 5.0 30.0 Flask Number Volume of buffered Iodide solution (mL) Volume of Thiosulfate solution (mL) Volume of water (mL) Volume of Peroxide solution (mL) Total Volume (mL) Stop Time (seconds) Start Time Total Time(seconds) Initial Temperature (°C)...
From the data table determine the rate law for reactions 1-4 and calculate the value of...
From the data table determine the rate law for reactions 1-4
and calculate the value of k for each. Thanks
I-IV
BACKGROUND
INFORMATION
Given: 3% H2O2 Concentration= 0.88M & 1.5% H2O2
Concentration= 0.44 M
•Calculation of H2O2 after mixing for parts I,II, IV= 0.704 M
•Calculation of I^- after mixing for parts I,II, IV= 0.10
M
•Calculation of Initial (mol/L-s)
Filled in Table
Now the solutions for Rate Order and Rate Constant are
needed
Reactants 8 ml 30% HO, 2...
using the data above calculate the moles of sodiumthiosulfate reacted and the mol/L of H2O2 21°...
using
the data above calculate the moles of sodiumthiosulfate reacted and
the mol/L of H2O2
21° + H2O2 + H 2 + H2O by varying reactant concentrations and reaction temperature. Results 3 40.0 40.0 40.0 40.0 10.0 10.0 10.0 5.0 20.0 10.0 20.0 0.0 30.0 5.0 30.0 10.0 Flask Number Volume of buffered lodide solution (mL) Volume of Thiosulfate solution (mL) Volume of water (mL) Volume of Peroxide solution (mL) Total Volume (mL) Stop Time (seconds) Start Time Total Time(...
EXPERIMENT 30 REPORT SHEET Rates of Chemical Reactions II: Rate and Order of H20, Decomposition 21.0...
EXPERIMENT 30 REPORT SHEET Rates of Chemical Reactions II: Rate and Order of H20, Decomposition 21.0 °C A. Order of Reaction BATH TEMPERATURE 21/C 21.5°C Solution Solution 2 Y Y Pret Burer reading Volofo reading Yolo Time (ml) (m) 20 QUOD 242 40 22 0.39 26.4 2.0 O. TESD 28+ SD 2.412 30.1 20.2 8.2 22.0 12.0 13 340 2412 120 22 Boy 12.0 2 LED 0.25 Time 4.2 Solution 3 Burer reading Vol of Time (m) 24.3 0.0 2.0...
How do I calculate the Rate of Reaction and the Relative Rate of Reaction? 0.04M 0.1M...
How do I calculate the Rate of Reaction and the Relative Rate of
Reaction?
0.04M 0.1M Initial I Concentration Initial S2082- Concentration Show a calculation of how you calculated the rate of reaction Rate of Reaction Use M/s to represent (mol/L)/s Show a calculation of how you calculated the relative rate of reaction Relative Rate of Reaction Reaction 1 Save&Continue Time to Colour Change 948 Numeric answers include a number followed by units. Nothing else. Pay attention to precision. Use...
Reaction 1 (10 mL undiluted 1.0% IKI and 5 mL undiluted 3% H2O2) Reaction 2 (10...
Reaction 1 (10 mL undiluted 1.0% IKI and 5 mL undiluted 3% H2O2) Reaction 2 (10 mL diluted 0.5% IKI and 5 ml undiluted 3% H2O2) Reaction 3 (10 mL undiluted 1.0% IKI and 5 mL diluted 2.25% H2O2) 13. Answer the following. ( a) How many moles of H2O2 are present in Reactions 1 and 2? Show your work (include units). Hint: The initial H2O2 solution is 3% m/v (mass/volume) hydrogen peroxide in water. That means that 3 g...
Table 1. Experimental Data Mass of Cylinder and solution: 35.1967g Mass of 10 mL cylinder before...
Table 1. Experimental Data
Mass of Cylinder and solution: 35.1967g
Mass of 10 mL cylinder before filling: 25.7418g
Mass of 10 mL cylinder after emptying: 25.7528g
Volume of solution in 10 mL cylinder: 9.56mL
Volume of gas in 100mL cylinder: 92.1mL
Temperature: 19.5C
Atmospheric Pressure: 29.98 inHg
Q3. 1,°C 17.0 18.0 Use the table of water's vapor pressure shown below. What is the vapor pressure in the unit needed for the ideal Gas Law? Record the vapor pressure in Table...
thanks in advance ☺ (A). For the hypothetical reaction A+B → C the following rate data...
thanks in advance ☺
(A). For the hypothetical reaction A+B → C the following rate data (with and without catalyst) were obtained: Rate, M/s Rate, M/s (A), M [B, M (uncatalyzed) (catalyzed) 0.100 0.200 3.51 x 10 4 7.14 x 10-2 0.100 0.100 1.75 x 104 7.14 x 10-2 0.0500 0.200 1.76 x 104 3.57 x 10-2 0.0500 0.100 8.80 x 10-5 3.57 x 10-2 Based on these data: a. Determine the uncatalyzed and catalyzed rate laws for this reaction,...
Rates of 30 Chemical Reactions II: Rate and Order of H202 Decomposition rder of Reaction H TEMPERATURE 20 oC 20 °c Solution 3 Solution 2 ution 1 uret ading Vol. ofO mL) (mL) Time (mL) Buretyol fO Time reading(mL) Buret reading Vol ofO (mL) Time (mL) /O 12 Slope Slope Slope Rate law: Since doubling either [H202] or [I] doubles the reaction rate the rate law is Rate Data Rate SolutionmL H20 5.0 10.0 5.0 mL KI (mL O2/s) 10.0...
Please help
V THIS IS THE DATA V
2. Calculate the mol/L H2O2 reacted or A[H2O2). (Include units on all values and report all results to 3 significant figures.). Trial 1 Trial 2 Trial 3 Trial 4 Experiment 5 Determining Rate of Reaction: lodide Oxidation by Hydrogen peroxide Purpose: To determine the rate law and activation energy for; 21 + H202 + H+ 12 + H2O by varying reactant concentrations and reaction temperature. Results 2 3 4 40.0 40.0 40.0...
using the data above answer 6-8
the
stock solution of H2O2 was 0.2M
21° + H2O2 + H 2 + H2O by varying reactant concentrations and reaction temperature. Results 40.0 40.0 40.0 40.0 10.0 10.0 10.0 5.0 10.0 20.0 20.0 10.0 0.0 30.0 5.0 30.0 Flask Number Volume of buffered Iodide solution (mL) Volume of Thiosulfate solution (mL) Volume of water (mL) Volume of Peroxide solution (mL) Total Volume (mL) Stop Time (seconds) Start Time Total Time(seconds) Initial Temperature (°C)...
From the data table determine the rate law for reactions 1-4
and calculate the value of k for each. Thanks
I-IV
BACKGROUND
INFORMATION
Given: 3% H2O2 Concentration= 0.88M & 1.5% H2O2
Concentration= 0.44 M
•Calculation of H2O2 after mixing for parts I,II, IV= 0.704 M
•Calculation of I^- after mixing for parts I,II, IV= 0.10
M
•Calculation of Initial (mol/L-s)
Filled in Table
Now the solutions for Rate Order and Rate Constant are
needed
Reactants 8 ml 30% HO, 2...
using
the data above calculate the moles of sodiumthiosulfate reacted and
the mol/L of H2O2
21° + H2O2 + H 2 + H2O by varying reactant concentrations and reaction temperature. Results 3 40.0 40.0 40.0 40.0 10.0 10.0 10.0 5.0 20.0 10.0 20.0 0.0 30.0 5.0 30.0 10.0 Flask Number Volume of buffered lodide solution (mL) Volume of Thiosulfate solution (mL) Volume of water (mL) Volume of Peroxide solution (mL) Total Volume (mL) Stop Time (seconds) Start Time Total Time(...
EXPERIMENT 30 REPORT SHEET Rates of Chemical Reactions II: Rate and Order of H20, Decomposition 21.0 °C A. Order of Reaction BATH TEMPERATURE 21/C 21.5°C Solution Solution 2 Y Y Pret Burer reading Volofo reading Yolo Time (ml) (m) 20 QUOD 242 40 22 0.39 26.4 2.0 O. TESD 28+ SD 2.412 30.1 20.2 8.2 22.0 12.0 13 340 2412 120 22 Boy 12.0 2 LED 0.25 Time 4.2 Solution 3 Burer reading Vol of Time (m) 24.3 0.0 2.0...
How do I calculate the Rate of Reaction and the Relative Rate of
Reaction?
0.04M 0.1M Initial I Concentration Initial S2082- Concentration Show a calculation of how you calculated the rate of reaction Rate of Reaction Use M/s to represent (mol/L)/s Show a calculation of how you calculated the relative rate of reaction Relative Rate of Reaction Reaction 1 Save&Continue Time to Colour Change 948 Numeric answers include a number followed by units. Nothing else. Pay attention to precision. Use...
Table 1. Experimental Data
Mass of Cylinder and solution: 35.1967g
Mass of 10 mL cylinder before filling: 25.7418g
Mass of 10 mL cylinder after emptying: 25.7528g
Volume of solution in 10 mL cylinder: 9.56mL
Volume of gas in 100mL cylinder: 92.1mL
Temperature: 19.5C
Atmospheric Pressure: 29.98 inHg
Q3. 1,°C 17.0 18.0 Use the table of water's vapor pressure shown below. What is the vapor pressure in the unit needed for the ideal Gas Law? Record the vapor pressure in Table...
thanks in advance ☺
(A). For the hypothetical reaction A+B → C the following rate data (with and without catalyst) were obtained: Rate, M/s Rate, M/s (A), M [B, M (uncatalyzed) (catalyzed) 0.100 0.200 3.51 x 10 4 7.14 x 10-2 0.100 0.100 1.75 x 104 7.14 x 10-2 0.0500 0.200 1.76 x 104 3.57 x 10-2 0.0500 0.100 8.80 x 10-5 3.57 x 10-2 Based on these data: a. Determine the uncatalyzed and catalyzed rate laws for this reaction,...
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