Please help
V THIS IS THE DATA V
Please help V THIS IS THE DATA V 2. Calculate the mol/L H2O2 reacted or A[H2O2)....
using the data above calculate the moles of sodiumthiosulfate reacted and the mol/L of H2O2 21° + H2O2 + H 2 + H2O by varying reactant concentrations and reaction temperature. Results 3 40.0 40.0 40.0 40.0 10.0 10.0 10.0 5.0 20.0 10.0 20.0 0.0 30.0 5.0 30.0 10.0 Flask Number Volume of buffered lodide solution (mL) Volume of Thiosulfate solution (mL) Volume of water (mL) Volume of Peroxide solution (mL) Total Volume (mL) Stop Time (seconds) Start Time Total Time(...
using the data above answer 6-8 the stock solution of H2O2 was 0.2M 21° + H2O2 + H 2 + H2O by varying reactant concentrations and reaction temperature. Results 40.0 40.0 40.0 40.0 10.0 10.0 10.0 5.0 10.0 20.0 20.0 10.0 0.0 30.0 5.0 30.0 Flask Number Volume of buffered Iodide solution (mL) Volume of Thiosulfate solution (mL) Volume of water (mL) Volume of Peroxide solution (mL) Total Volume (mL) Stop Time (seconds) Start Time Total Time(seconds) Initial Temperature (°C)...
The reaction 2H2O2(aq)→2H2O(l)+O2(g) is first order in H2O2 and under certain conditions has a rate constant of 0.00752 s−1 at 20.0 ∘C. A reaction vessel initially contains 150.0 mL of 30.0% H2O2 by mass solution (the density of the solution is 1.11 g/mL). The gaseous oxygen is collected over water at 20.0 ∘C as it forms. What volume of O2 will form in 73.9 seconds at a barometric pressure of 719.5 mmHg . (The vapor pressure of water at this...
thjs is the question this is the data these are the background information please help thank you 4. Approximate the number of moles of hydrogen peroxide at the equivalence point in the graph in the introduction, supposing a 3.00% m/m solution. Thus the densities will be- Trial Mass(g) 0.448 0.450 3 Density(g/ml) 0.448 g/ 0.400 ml = 1.12 g/ml 0.450 g/ 0.400 ml = 1.125 g/ml 0.437 g/ 0.400 ml = 1.0925 g/m 0.442 g/ 0.400 ml = 1.105 g/ml...
2 H2O2(aq) + 2 H2O(l) + O2(g) 5. Hydrogen peroxide decomposes according to the equation above. a. An aqueous solution of H2O, that is 6.00 percent H,O, by mass has a density of 1.03 g ml. Calculate each of the following. (i) The original number of moles of H2O, in a 125 ml sample of the 6.00 percent H2O2 solution (ii) The number of moles of O,(g) that are produced when all of the H2O2 in the 125 mL sample...
is 23 right? and can you answer 24/25 2 pts D Question 23 A 0.300 M solution of LiOH that contains 0.600 mole of solute would have a volume, in milliliters, of 30.0 mL O 2.00 x 10 ml 1.67 x 10mL 6.00 x 10 ml D Question 24 2 pts Which of the following solutions will have a molarity of greater than 1.0 after 50.0 mL of solvent is added to it? 40.0 mL of 2.0 M solution 175...
4. Experimental Procedure, Part A, Table 5.1 a. In Trial 1, what is the function of the sodium thiosulfate in studying the kinetics of the hydrogen peroxide-iodide reaction? b. Calculate the moles of S,0,2 that are consumed during the course of the reaction in Trial 1 produced during the course of the reaction. See equation 5.1 that are c. Calculate the moles of I Eveian 3 noitoviioA b d. Calculate the initial molar concentration of I (at time 0), [I...
Alkalinity Determination and Titration: Please Help, with questions I answered. Equivalance 1(EP1)= 27.5mL, at 8.25pH ; Equivalance 2(EP2) = 61mL, at 4.28pH HCl=0.1 M 20mL of unknown solution gathered Determining the moles of carbonate ion: The first EP is the first protonation of the carbonate ions. HCl = 0.1M Moles of CO;2- = (0.100 M*(0.0275L)/(0.02L)=1.375 M Determining the moles of bicarbonate ion: The second EP is the protonation of bicarbonate ions AND the second protonation of carbonate ions. Moles of...
Spot Construction builds roads, bridges, and other infrastructure. The following is the budget for a road project along with the actual results (in thousands of dollars) for the last fifteen months. Month 1 m in Actual Cost Complete $ 0 0.0% $ 700 5.5% $ 1,160 11.2% $ 1,820 13.4% $ 2,270 21.6% $ 2,810 27.5% $ 3,190 34.0% $ 3,870 36.5% $ 4,200 45.0% $ 4,710 48.8% $ 5,400 53.4% $ 5,920 56.7% $ 6,300 62.3% $ 7,190 70.0%...
Suggested Data Table (Partially completed) 1 2 3 4 5 6 7 8 9 10 11 Vol HX Init., mL Vol OH– added for this increment, mL Total Vol OH–, mL Total Vol Soln, mL [HX]i [X–]eq [HX]eq [X–]/[HX] log Meas'd pH Calc'd pKa 0 50.0 0.0 0.0 50.0 --- --- --- --- --- --- --- 1 50.0 10.0 10.0 60.0 2 50.0 5.0 15.0 65.0 3 50.0 5.0 20.0 70.0 4 50.0 10.0 5 50.0 6 50.0 please help...