Question

The standard voltage of the voltaic cell (E ° cell) based on the given half-reactions and...

The standard voltage of the voltaic cell (E ° cell) based on the given half-reactions and the number of moons of electrons (n) transferred in the redox reaction are:
Ni2 + (ac) + 2e- = Ni (s) E ° = -0.25V
Al3 + (ac) + 3e- = Al (s) E ° = -1.66V

A. E ° cell = -1.91V and n = 5 mol e-
B. E ° cell = + 1.91V and n = 6 mol e-
C. E ° cell = + 1.91V and n = 5 mol e-
D. E ° cell = + 1.41V and n = 6 mol e-
E. E ° cell = + 1.41V and n = 5 mol e-

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
The standard voltage of the voltaic cell (E ° cell) based on the given half-reactions and...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • I need help with questione 1-12 and discussion question 1 and 2. The previous pictures help...

    I need help with questione 1-12 and discussion question 1 and 2. The previous pictures help determine the chart. Please Show Work thank you so much An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...

  • Calculate the maximum standard voltage possible for a voltaic cell based on the following half reactions:...

    Calculate the maximum standard voltage possible for a voltaic cell based on the following half reactions: E°/V Cu(aq)+2e-→Cu(s) +0.34 Ca2+(aq)+2e-→Ca(s) -2.87    +2.53 V    -2.53 V    +3.21 V    +1.26 V What is the standard reduction potential for Ba2+ if a Cu-Ba voltaic cell generates 3.24 V with Cu being reduced? (E° for Cu(II) to Cu is +0.34 V)    -2.90 V    -3.58 V    +3.58 V    +2.90 V

  • A voltaic cell is constructed from a standard Co2+ Co half cell (Eºred = -0.280V) and...

    A voltaic cell is constructed from a standard Co2+ Co half cell (Eºred = -0.280V) and a standard Ar Al half cell (Ered=-1.660V The anode reaction is: The cathode reaction is: The spontaneous cell reaction is: The cell voltage is Enter electrons as e A voltaic cell is constructed from a standard Ni Ni half cell (Ered -0.250V) and a standard BryBr half cell (Ered =1.080V). (Use the lowest possible coefficients. Use the pull down boxes to specify states such...

  • Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is...

    Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...

  • If you construct a Galvanic / Voltaic cell using a Ni(s) / Ni2+(aq) half cell and...

    If you construct a Galvanic / Voltaic cell using a Ni(s) / Ni2+(aq) half cell and an Al(s)/ Al3+(aq)half cell,and connect the whole cell to a voltmeter by connecting the Al half cell to the positive terminal of the voltmeter, what will be the display?

  • A voltaic cell is constructed from a standard Fe2+|Fe half cell (E°red = -0.440V) and a...

    A voltaic cell is constructed from a standard Fe2+|Fe half cell (E°red = -0.440V) and a standard Cl2|Cl- half cell (E°red = 1.360V) Anode Reaction: Cathode Reaction: Spontaneous Cell Reaction: Cell Voltage: ___ V A voltaic cell is constructed from a standard Fe2+|Fe half cell (E°red = -0.440V) and a standard Al3+|Al half cell (E°red = -1.660V). Anode Reaction: Cathode Reaction: Spontaneous Cell Reaction: Cell Voltage: ___ V

  • A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25 ∘C. The...

    A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25 ∘C. The initial concentrations of Ni2+ and Zn2+ are 1.80 molL−1 and 0.130 molL−1, respectively. Zn2+(aq)+2e−→Zn(s)E∘=−0.76V Ni2+(aq)+2e−→Ni(s)E∘=−0.23V A) What is the cell potential when the concentration of Ni2+ has fallen to 0.600 molL−1? B) What are the concentrations of Ni2+ and Zn2+ when the cell potential falls to 0.45 V?

  • Given the following half reactions what is the voltage of the galvanic cell that would result...

    Given the following half reactions what is the voltage of the galvanic cell that would result from their combination [maximum positive voltage and spontaneous reaction). Show work. E° (volts) -0.74 Cr3+ (aq) + 3e Cu2+ (aq) + 2e → → Cr (8) Cu (s) +0.34 And what is the overall reaction that results after the half reactions are combined to cancel all electrons. Show work. And fill in the following abbreviated cell to represent the actual galvanic cell from above.

  • A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25 ∘C. The...

    A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25 ∘C. The initial concentrations of Ni2+ and Zn2+ are 1.60molL−1 and 0.130 molL−1, respectively. Zn2+(aq)+2e−→Zn(s)E∘=−0.76V Ni2+(aq)+2e−→Ni(s)E∘=−0.23V Part A What is the initial cell potential? Part B What is the cell potential when the concentration of Ni2+ has fallen to 0.600 molL−1? Part C What are the concentrations of Ni2+ and Zn2+ when the cell potential falls to 0.45 V?

  • The standard reduction potentials of the following half-reactions are given in Appendix E in the textbook:...

    The standard reduction potentials of the following half-reactions are given in Appendix E in the textbook: Ag+(aq)+e−→Ag(s)= .799 Cu2+(aq)+2e−→Cu(s)= .337 Ni2+(aq)+2e−→Ni(s)= -.28 Cr3+(aq)+3e−→Cr(s). = -.74 1. Determine which combination of these half-cell reactions leads to the cell reaction with the largest positive cell emf. 1st and 2nd, 1st and 3rd, 1st and 4th, 2nd and 3rd, 3rd and 4th. It isn't the first or last one because I have gotten it wrong twice. 2. Calculate the value of this emf....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT