Question

this Question: 2 pts 3 of 11 (0 complete) This Quiz: 17 pts possible Question Help Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of O and a standard deviation of 1. Draw a graph and find Po, the 6th percentile. This is the bone density score separating the bottom 6% from the top 94% "Which graph represents Po? Choose the correct graph below. SA ов. OC OD w r Р. Р. The bone density score corresponding to P is Round to two decimal places as needed.) ck to select your answer(s).

Answer 1

For graph, option (D) is correct.

Since mean is 0 and standard deviation is 1 , we can assume Standard normal distribution.

Thus

P( Z < z value ) = 0.06 (6%)


Look for z value on z table for area = 0.06 or its closest area.

P( Z < z value ) = 0.06 (6%)
z value= -1.55

The bone density score corresponding to P₆ is -1.55.