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A diffuser, flowing R134a, has a mass flow rate of 5.0 kg/s. At the inlet, the R134a is a saturated vapor at 20°C with a velo
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Answer #1

So mass flow rate of saturated vapoue is given by

\frac{dm}{dt}=\rho _sAv

here \rho _s is density of saturated vapour at 20 degree centigrad which is from table we get 17.3 gm /m^3 or

=0.0173 kg/m^3

and

v is velocity of flow =100m/s

and mass flow rate is 5kg/s

so we solve for A and get

5= (0.0173)A(100)

so, area of diffuser

A= 2.89m^2

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